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 Percentage Questions

Popular Latest Rated Important Formulae

FACTS  AND  FORMULAE  FOR  PERCENTAGE  QUESTIONS

 

 

I.Concept of Percentage : By a certain percent , we mean that many hundredths. Thus x percent means x hundredths, written as x%.

To express x% as a fraction : We have , x% = x/100.

Thus, 20% = 20/100 = 1/5;     

48% = 48/100 = 12/25, etc.

To express a/b as a percent : We have, ab=ab×100% .

 

Thus, 14=14×100%=25%

   

 

II. If the price of a commodity increases by R%, then the reduction in consumption so as not to increase the expenditure is R100+R×100%

If the price of the commodity decreases by R%,then the increase in consumption so as to decrease the expenditure is R100-R×100%

 

 

III. Results on Population : Let the population of the town be P now and suppose it increases at the rate of R% per annum, then :

1. Population after n years = P1+R100n

 

2. Population n years ago =  P1+R100n

 

 

IV. Results on Depreciation : Let the present value of a machine be P. Suppose it depreciates at the rate R% per annum. Then,

1. Value of the machine after n years = P1-R100n

 

2. Value of the machine n years ago = P1-R100n

 

 

V. If A is R% more than B, then B is less than A by

R100+R×100%    

If A is R% less than B , then B is more than A by 

R100-R×100%  

Q:

Sneha’s weight is 140% of Veena’s weight. Rina’s weight is 90% of Sana’s weight. Sana weighs twice as much as Veena. If Sneha’s weight is x% of Rina’s weight, then x is equal to:

A) 596/9 B) 605/9
C) 645/9 D) 700/9
 
Answer & Explanation Answer: D) 700/9

Explanation:

Let Veena's weight = 1 kg

Sana's weight = 2 kg

Sneha's weight = 1.4 kg

Rina's weight = 1.8 kg

Now,according to the given data in the question,

1.8x100 = 1.4

 

x = 1.4 × 1001.8 = 7009 = 77 79.

 

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8 5916
Q:

A user type a content on 20 sheets, each sheet consist of 55 lines, and each line can have 66 characters. The content is again retyped on another set of sheets, these new sheets have 65 lines and each line can take 70 characters. Calculate the reduction in sheets ?

A) 2 or 60% B) 4 or 20%
C) 6 or 10% D) 8 or 5%
 
Answer & Explanation Answer: B) 4 or 20%

Explanation:

20 x 55 x 66 = L x 65 x 70
Here L = 72,600/4550 = 15.95 =~ 16
Reduction is 20-16 = 4

which is 20% reduction.

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3 5888
Q:

In a competitive examination, the average marks for the entire examination was 60 marks. If 20% of the applicants scored 85 marks and 25% scored 95 marks. What was the average marks of the remaining applicants in the examination ?

A) 60 B) 52
C) 45 D) 35
 
Answer & Explanation Answer: D) 35

Explanation:

Let the total applicants be 100

 

Then, 20% got 85 marks

i.e 20 x 85 = 1700

 

and 25% got 95 marks

 i.e 25 x 95 = 2375

 

Now, the remaining applicants are 55 and let the average marks scored by them be x.

 

Therefore, 2375 + 1700 + 55x  =  60×100 

6000 - 4075 = 55x

55x=1925

x=35.

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8 5879
Q:

Madhu got 32% of the maximum marks in a Bank examination and failed by 8 marks. However, Kumar who took the same examination got 42% of the total marks and got 16 marks more than the cut-off marks. What was the cut-off marks in the examination ?

A) 76.8 B) 86.8
C) 78.8 D) 84.8
 
Answer & Explanation Answer: D) 84.8

Explanation:

Let 'M' be the maximum marks in the examination.

Therefore, Madhu got 32% of M = 32M/100 = 0.32M
And Kumar got 42% of M = 42M/100 = 0.42M.
In terms of the maximum marks Kumar got 0.42M - 0.32M = 0.1M more than Madhu. ---- (1)

The problem however, states that Kumar got 16 marks more than the cut-off mark and Madhu got 8 marks less than the cut-off mark. Therefore, Kumar has got 16 + 8 = 24 marks more than Madhu. ---- (2)

Now, Equating (1) and (2), we get
0.1M = 24 => M = 24/0.1 = 240
'M' is the maximum mark and is equal to 240 marks.
We know that Madhu got 32% of the maximum marks.
Therefore, Madhu got 32 x 240/100 = 76.8 marks.
We also know that Madhu got 8 marks less than the cut-off marks.

Therefore, the cut-off marks will be 8 marks more than what Madhu got
= 76.8 + 8 = 84.8.

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11 5843
Q:

Population of a colony of mosquitoes is increasing by 20% per day. If the population on Monday was 3000, on which day of that week the population would be 5184 ?

A) Thursday B) Friday
C) Tuesday D) Monday
 
Answer & Explanation Answer: A) Thursday

Explanation:

Given monday population = 3000
Per day 20% increase in population.

Tuesday population = 3000 + 3000x20/100 = 3000 + 600 = 3600

Wednesday population =3600 + 3600x20/100 = 3600 + 720 = 4320

Thursday population = 4320 + 4320x20/100 = 4320 + 864 = 5184

So that day is Thursday.

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3 5809
Q:

74.99% of 1299 + 8.98% of 1899 = ? 

A) 1378 B) 1301
C) 1212 D) 1197
 
Answer & Explanation Answer: C) 1212

Explanation:

74.99% of 1299 + 8.98% of 1899 = ? 

? = 75 x 1400100 + 9 x 1800100 ? = 1050 + 162? = 1212.

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9 5804
Q:

75% of 450 + ? % of 560 = 600 

A) 52.385 B) 46.875
C) 42.155 D) 40.555
 
Answer & Explanation Answer: B) 46.875

Explanation:

75% of 450 + ? % of 560 = 600 

75 x 450100 + ? x 560100 = 60075 x 92 + 28p5 = 60075x9x5 + 56p10 = 6003375 + 56p = 600056p = 2625p = 46.875

 

Hence, in the given question ? = 46.875

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3 5801
Q:

A jar can 20 litre milk. From the jar, 4 litres milk was taken out and replaced with an equal quantity of water. If 4 litres of the newly formed mixture is taken out of the can, then what is the final quantity of milk left in the can?

A) 14.5 lit B) 12.8 lit
C) 11.6 lit D) 10.46 lit
 
Answer & Explanation Answer: B) 12.8 lit

Explanation:

This can be solved as

 

20 1 - 4202  =  20 1 - 152= 20452= 20 1625= 645= 12.8

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11 5769