1
Q:
| A) C3+ (g) → C4+ (g) + e- | B) C (g) → C+ (g) + e- |
| C) C2+ (g) → C3+ (g) + e- | D) C+ (g) → C2+ (g) + e- |
Answer: A) C3+ (g) → C4+ (g) + e-
Explanation:
Explanation:
We know that each successive IE is greater than the previous one, because each ionization process removes one electron and hence increases the total attractive force on the remaining electrons from the nucleus. Hence, C3+ (g) → C4+ (g) + e- needs more energy.
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