Common Admission Test (CAT) Questions and Answers with Explanation

Q:

Which compound contains both ionic and covalent bonds?

A) NaNO3	B) CaSO4
C) NH4Cl	D) All of the above

Answer & Explanation Answer: D) All of the above

Explanation:

Here all the given compounds have both ionic and covalent bonds.

NaNO3 - In Sodium nitrate, Nitrate is covalently bonded as nitrogen is bonded with 3 oxygen atoms. And this nitrate is ionically bonded with sodium.

CaSO4 - In Calcium sulphate, sulphate is covalently bonded as sulphur is bonded with 4 oxygen atoms. And this sulphate is ionically bonded with calcium.

NH4Cl - In Ammonium chloride, ammonium is covalently bonded as nitrogen is bonded with 4 hydrogen atoms. And this ammonium is ionically bonded with chlorine.

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Q:

When was Uttarakhand separated from Uttar pradesh to form new state ?

A) 1997	B) 1998
C) 1999	D) 2000

Answer & Explanation Answer: D) 2000

Explanation:

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Filed Under: Indian Geography
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Q:

Porcupine : Rodent :: Mildew : ?

A) Insect	B) Fungus
C) Pathogen	D) Germ

Answer & Explanation Answer: B) Fungus

Explanation:

Porcupine is a rodent and mildew is a fungus.

Hence, Porcupine : Rodent :: Mildew : Fungus.

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Q:

Ajay who is a King, at his eleventh hour, called his three queens and distributed his gold in the following way: He gave 50% of his wealth to his first wife, 50% of the rest to his second wife and again 50% of the rest to his third wife. If their combined share is worth1,30,900 kilograms of gold, find the quantity of gold King Ajay was having initially?

A) 153145 kgs	B) 147890 kgs
C) 152400 kgs	D) 149600 kgs

Answer & Explanation Answer: D) 149600 kgs

Explanation:

Let the total quantity of gold be p kgs.

According to the question,

50% of p + 25% of p + 12.5% of p = 130900

87.5% of p = 130900

p = 130900 x 100/87.5 = 149600 kgs.

Therefore, the initial gold quantity that king has = p = 149600 kgs.

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Filed Under: Percentage
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Q:

43% of 616.6 + 37% of 217 =?

A) 345.428	B) 354.428
C) 344.428	D) 364.428

Answer & Explanation Answer: A) 345.428

Explanation:

43 x 616.6/100 + 37 x 217/100

=> 265.138 + 80.29

=> 345.428

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Q:

Which of the following pairs have the same relationship as OFTEN : FOTEN?

A) HEART : TRAHE	B) OPENS : SNEOP
C) RISKY : IRSYK	D) FIRST : IFRST

Answer & Explanation Answer: C) RISKY : IRSYK

Explanation:

It is a case of shifting as given below:

1 2 3 4 5 2 1 3 5 4

O F T E N $\to$ F O T N E

---------------------------------------------------------------------------

1 2 3 4 5 5 4 3 1 2

1. H E A R T $\to$ T R A H E

2. O P E N S $\to$ S N E O P

1 2 3 4 5 2 1 3 5 4

3. R I S K Y $\to$ I R S Y K

4. F I R S T $\to$ I F R S T

Hence option 3 is correct.

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Q:

A plane is an undefined term because it

A) is a flat surface that extends indefinitely in all directions	B) is where other geometric shapes can be constructed
C) is described generally, not using a formal definition	D) can be named using three noncollinear points

Answer & Explanation Answer: C) is described generally, not using a formal definition

Explanation:

In geometry, we can define plane as a flat surface with no thickness.

The surface extends with no ends.

A plane does not have any edges even if we draw it on paper with edges, it does't mean it has edges.

Hence, A plane is an undefined term because it is described generally, not using a formal definition.

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Q:

P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?

A) 99	B) 100
C) 89	D) 1

Answer & Explanation Answer: A) 99

Explanation:

Let, Distance between A and B = d

Distance travelled by P while it meets Q = d + 11

Distance travelled by Q while it meets P = d – 11

Distance travelled by Q while it meets R = d + 9

Distance travelled by R while it meets Q = d – 9

Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11

The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9

But given Ratio of speeds of P & R => P : R = 3 : 2

$\frac{S P}{S R} = \frac{S P}{S Q} x \frac{S Q}{S R} = \frac{(d + 11) (d + 9)}{(d - 11) (d - 9)}$

=> $\frac{(d + 11) (d + 9)}{(d - 11) (d - 9)}$ = 3/2

=> d = 1, 99

=> d = 99 satisfies.

Therefore, Distance between A and B = 99

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Filed Under: Time and Distance
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