CAT Questions

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Given the cost price of the articles = Rs. 450

To get overall 20% gain,

Total Selling Price = (20/100) x 450 = 540

One third of the CP = 1/3 x 450 = Rs. 150

But given 1/3 of articles are sold at 10% loss

S.P of 1/3 of articles = 90% of 150

= 90 x 150/100 = 135

Then, S.P on remaining 2/3 goods must be

= 450 - 135 = 405 ...........(1)

CP on remaining goods

= 2/3 x 450 = 300 ............(2)

Profit = SP - CP = 405 - 300 = 105

Profit %  = (105/300) x 100

= 35%.

Computer was invented by Charles Babbage.

The First Mechanical Computer Designed by Charles Babbage, a British mathematician was called as Analytical Engine which resembles today's modern machines  between 1833 and 1871.

We have : ( a + b + c) / 3 = M   or (a + b + c) = 3M.

Now. a+b+c2=3M2=9M2 .

<=>a2+b2+c2+2ab+bc+ca=9M2

a2+b2+c2=9M2 ,(ab+bc+ca=0)     

Required mean =a2+b2+c23=9M23=3M2 .

Kunnathur is the Smallest Taluk in Kerala State.

Taluk :

In Kerala, the administrative divisions below the district are called Taluk. There are 77 Taluks in Kerala State.

Eranad is the Largest Taluk in Kerala State.

Palakkad is the Largest District in Kerala State.

Alappuzha is the Smallest District in Kerala State.

Paramagnetic Molecules ::

If the Electronic configuration of a molecule has any unpaired electrons, then that molecule is said to be Paramagnetic.

Diamagnetic Molecules ::

If the Electronic configuration of a molecule has only paired or spin paired electrons, then that molecule is said to be Diamagnetic.

Here the molecule C2 has all paired electrons in its electronic configuration. So C2 is Diamagnetic.

Whereas, B2 molecule has unpaired electrons. So B2 is Paramegnetic.

A red ball can be drawn in two mutually exclusive ways

 (i) Selecting bag I and then drawing a red ball from it.

(ii) Selecting bag II and then drawing a red ball from it.

Let E1, E2 and A denote the events defined as follows:

E1 = selecting bag I,

E2 = selecting bag II

A = drawing a red ball

Since one of the two bags is selected randomly, therefore 

P(E1) = 1/2  and  P(E2) = 1/2

Now, PAE1 = Probability of drawing a red ball when the first bag has been selected = 4/7

  PAE2  = Probability of drawing a red ball when the second bag has been selected = 2/6

 Using the law of total probability, we have 

 P(red ball) = P(A) = PE1×PAE1+PE2×PAE2 

                          = 12×47+12×26=1942

Number of persons between Amrita and Mukul = 50 - (10 + 25) = 15. Since Mamta lies in middle of these 15 persons, so Mamta`s position is 8th from Amrita i.e. 18th from the front.