CAT Questions

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Total time taken = k/40 + 2k/20 hours

= 5k/40 = k/8 hours

Average speed = 3k/(k/8) = 24 kmph.

3300 ----- 3% ↑ (1st time interval, 99) → 3399.

Here, time interval is given as half-yearly i.e. 6 months.

p=d×1002R2 

Where d is difference, r is rate of interest. 

=> (48 x 100 x 100) / 8 x 8 = Rs.7500

Let, Hema attempted 'k' sum correctly, then

k x 3 -2 x(35-k) = 60
5k = 130
k = 26

so 26 correct sums.

With a positive attitude you see the bright side of life, become optimistic, and expect the best to happen. It is certainly a state of mind that is well worth developing. Not only it enriches one’s experience of life, but it also paves the way for self-development leading one towards attaining the desired results. As regards employment, it is a valuable thing to maintain positive attitude. Whether you are a manager or a subordinate, maintaining positive attitude in the work place brings lots of benefits while allowing you to fulfill your objectives successfully.
A positive frame of mind can help you in many ways, such as:
- Making you feel inspired.
- Identification.
- Believing in yourself and in your abilities.
- You look for solutions, instead of dwelling on problems.
- The most important thing is building relations.

Interest received by L from K = 8% of half of Rs.40,000  

⇒8100×20000=1600  

Amount received by L per annum for being a working partner = 1200 x 12 = Rs.14,400

Let 'A' be the part of remaing profit that 'L' receives as his share.

 Total income of 'K' = only his share from the reamaing profit

                              = 'A', as both share equally.

Given income of L = Twice the income of K

--> (1600 + 14400 + A ) = 2A

--> A= Rs.16000

Thus total profit = 2A + Rs.14,400= 2(16000) + 14400 

                                                  = 32000 +14400 = Rs.46,400.

Total work is given by L.C.M of 72, 48, 36

Total work = 144 units

Efficieny of A = 144/72 = 2 units/day

Efficieny of B = 144/48 = 3 units/day

Efficieny of C = 144/36 = 4 units/day

According to the given data,

2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100

3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54

p = 198/16.5

p = 12 days.

Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day

(C+D) in p days = (4 + 6) x 12 = 120 unit

Remained part of work = (144-120)/144 = 1/6.

Suppose they meet after 'h' hours

Then

3h + 4h = 17.5

7h = 17.5

h = 2.5 hours

So they meet at => 4 + 2.5 = 6:30 pm