CAT Questions

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From the given data,

P = 140

But it is given that,

40% of Q + Q = 140 = P

=> Q + [40Q/100] = 140

=> [100Q + 40Q]/100 = 140

=> 140Q = 140 x 100

=> Q = 100

Now,

 3/25 of Q 

= (3/25) x 100

= 3 x 4 

= 12 

Required 3/25 of Q  = 12.

Here among the given numbers, 3, 19, 67 are prime numbers. And 133 is not a prime number.

Hence, the odd number of the given numbers is 133.

For this we have to find the LCM of 24, 36 and 30

LCM of 24, 36 and 30 = 360 sec

360/60 min = 6 minutes.

Now, the distance covered by Chennai express in 2 hrs = 60 x 2 = 120 kms

Let the Charminar Express takes 't' hrs to catch Chennai express

=> 80 x t = 60 x (2 + t)

=> 80 t = 120 + 60t

=> t = 6 hrs

Therefore, the distance away from Hyderabad the two trains meet = 80 x 6 = 480 kms.

As these three strategies P, Q and R are independent so these will cut cost one after the other.
If initial cost is Rs 100, then
20% cost is cut after initializing strategy P, then cost will remain 80% = 80
further 30% cost is cut after strategy Q, then cost will remain 70% of 80 = 56
further 10% cost is cut after strategy R, then cost will remain 90% of 56 = 50.4

Thus final cost remains 50.4 % of the original cost. Hence net saving is 100 - 50.4 = 49.6 %.

Here 40% of 80 is given as

40100 x 80 = 8 x 4 = 32

Cost of 4 mangoes = Rs. 6 

Cost of 1 mango = Rs. 6/4 = Rs. 1.5

Now, Selling Price of 4 mangoes = Rs. 4

Selling Price of 1 mango = Rs. 4/4 = Rs. 1.0

• We observe that, S.P < C.P

Hence, the shopkeeper incurs a loss.

Required loss% = loss/C.P x 100

Loss = 1.5 - 1 = 0.5

C.P = 1.5

Loss% = (0.5/1.5) x 100

 = (5/15) x 100

 = 1/3 x 100

 = 100/3

 = 33.333%.