Questions

#include <stdio.h>

int main() {

  int a[5][5], b[5][5], c[5][5], i, j, k, sum = 0, m, n, o, p;

  printf( "\nEnter the row and column of first matrix" );

  scanf( "%d %d", &m, &n );

  printf( "\nEnter the row and column of second matrix" );

  scanf( "%d %d", &o, &p );

  if(n!=o) {

      printf( "Matrix mutiplication is not possible" );

      printf( "\nColumn of first matrix must be same as row of second matrix" );

  }

  else {

      printf( "\nEnter the First matrix" );

      for( i=0; i<m; i++ )

      for( j=0; j<n; j++ )

           scanf( "%d", &a[i][j] );

      printf( "\nEnter the Second matrix" );

      for( i=0; i<o; i++ )

      for( j=0; j<p; j++ )

           scanf( "%d", &b[i][j] );

      printf( "\nThe First matrix is\n" );

      for( i=0; i<m; i++ ) {

      printf("\n");

      for( j=0; j<n; j++ ) {

           printf( "%d\t", a[i][j] );

      }

      }

      printf( "\nThe Second matrix is\n" );

      for( i=0; i<o; i++ ) {

      printf("\n");

      for( j=0; j<p; j++ ) {

           printf( "%d\t", b[i][j] );

      }       

      }

      for( i=0; i<m; i++ )

      for( j=0; j<p;j++ )

           c[i][j] = 0;

      for( i=0; i<m; i++ ) { //row of first matrix

      for( j=0; j<p; j++ )  {  //column of second matrix

           sum = 0;

           for( k=0; k<n; k++ )

               sum = sum + a[i][k]*b[k][j];

           c[i][j] = sum;

      }

      }

  }

  printf( "\nThe multiplication of two matrix is\n" );

  for( i=0; i<m; i++ ) {

      printf("\n");

      for( j=0; j<p; j++ ) {

           printf( "%d\t", c[i][j] );

      }

  }

  return 0;

}

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Primary productivity refers to plants that make their own food using sunlight, water and availability of nutrients. Hence, they are not limited by time.