Questions

65292

1st digit is 3 x 2 = 6

3rd digit is 5-3 = 2

4th digit is 5+4 = 9 

6+5 = 2+9 = 9+2 = 11

? = 4 + 85/4

? = 5.01

A concentrated solution will contain the most solute molecules per solvent molecules.

Here in the given options,

1)  6/10 = 0.6

2) 20.5/50 = 0.41

3) 30/120 = 0.25

4) 2.6/2 = 1.3

Hence, option D) is most concentrated.

Tezpur is the city in the state of Assam is known as City of Blood.

Australia is the smallest of all the continents

The code segments B and D will compile without any error. A is not a valid way to construct a StringBuffer, you need to create a StringBuffer object using "new". B is a valid construction of a Boolean (any string other than "true" or "false" to the Boolean constructor will result in a Boolean with a value of "false"). C will fail to compile because the valid range for a byte is -128 to +127 (i.e., 8 bits, signed). D is correct, 0x1234 is the hexadecimal representation in java. E fails to compile because the compiler interprets 1.2 as a double being assigned to a float (down-casting), which is not valid. You either need an explicit cast, as in "(float)1.2" or "1.2f", to indicate a float.