Questions

An ionic bond is formed in between the two atoms with the transfer of electrons from an atom to the other to become stable after pairing.

The atom which has low ionization energy will give some of its electrons to get stable electronic configuration .

Farming in the early New England colonies was challenging because unfamiliar weather and soil conditions affected cultivation.

I. Inputs

• Enterprise environmental factors


• Organizational process assets


• Project scope statement


• Activity list


• Activity attributes


• Activity resource requirements


• Resource calendars


• Project management plan

               - Risk register

               - Activity cost estimates

II. Tools and Techniques

• Expert judgment


• Analogous  estimating


• Parametric estimating


• Three-point estimates 


• Reserve analysis

III. Outputs

• Activity duration estimates


• Activity attributes (updates)

#include
#define MAX 50

void mergeSort(int arr[],int low,int mid,int high);
void partition(int arr[],int low,int high);

int main(){
  
    int merge[MAX],i,n;

    printf("Enter the total number of elements: ");
    scanf("%d",&n);

    printf("Enter the elements which to be sort: ");
    for(i=0;i<n;i++){
         scanf("%d",&merge[i]);
    }

    partition(merge,0,n-1);

    printf("After merge sorting elements are: ");
    for(i=0;i<n;i++){
         printf("%d ",merge[i]);
    }

   return 0;
}

void partition(int arr[],int low,int high){

    int mid;

    if(low<high){
         mid=(low+high)/2;
         partition(arr,low,mid);
         partition(arr,mid+1,high);
         mergeSort(arr,low,mid,high);
    }
}

void mergeSort(int arr[],int low,int mid,int high){

    int i,m,k,l,temp[MAX];

    l=low;
    i=low;
    m=mid+1;

    while((l<=mid)&&(m<=high)){

         if(arr[l]<=arr[m]){
             temp[i]=arr[l];
             l++;
         }
         else{
             temp[i]=arr[m];
             m++;
         }
         i++;
    }

    if(l>mid){
         for(k=m;k<=high;k++){
             temp[i]=arr[k];
             i++;
         }
    }
    else{
         for(k=l;k<=mid;k++){
             temp[i]=arr[k];
             i++;
         }
    }
  
    for(k=low;k<=high;k++){
         arr[k]=temp[k];
    }
}


Sample output:

Enter the total number of elements: 5
Enter the elements which to be sort: 2 5 0 9 1
After merge sorting elements are: 0 1 2 5 9