There is a cylinder circumscribing the hemisphere such that their bases are common. Find the ratio of their volumes
R =OA = OB = Radius of hemisphere.= Radius of cylinder ABCD.Height of the cylinder = BC = radius
Volume of cylinder/Volume of hemisphere = πr323πr3
Find the ratio of the surfaces of the inscribed and circumscribed spheres about a cube.
4×3.14×r2 : 4×3.14×r2 = 1 : 2
A cylindrical rod of iron, whose height is equal to its radius, is melted and cast into spherical balls whose radius is half the radius of the rod. Find the number of balls.
Volume of rod = πr2h = πr2×r = πr3
Volume of one spherical ball =r/2
Volume of the spherical ball = 43πr38
Number of balls=Volumeof rod/volumeof one ball
Two cylindrical buckets have their diameters in the ratio 3:1 and their heights are as 1: 3. Find the ratio of their volumes.
d1 = 2r1 and d2 = 2r2 are diameters
If the radius of base and height of a cone are increased by 10%, find the percentage of increase of its volume
% Increase in volume = (V2-V1) / (V2*100)
Two cones have their heights in the ratio 1:3 and the radii of their bases in the ratio 3:1. Find the ratio of their volumes.
What is the true discount on a bill of Rs.2916 due in 3 years hence at 8% C.I.?
PW = Amount1+R100T
The present value of a bill due at the end of 2 years is Rs.1250. If the bill were due at the end of 2 years and 11 months, its present worth would be Rs.1200. Find the rate of interest and the sum.
PW = 100×Amount100+R×T
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