Project Manager Questions

Here in this declaration public static void main string[] args, each keyword has its importance.

1. public - Here public is an access specifier which allows the main method to be accessible everywhere.

2. static - static helps the main method to get loaded without getting called by any instance/object.

3. void - void clarifies that the main method will not return any value.

4. main - It's the name of the method.

5. String[] args - Here we are defining a String array to pass arguments at the command line. args is the variable name of the String array.

1 TB  >  1 GB  >  1 MB  >  1 KB

1 Tb (Tera Byte) = 1024 GB

1 GB (Giga Byte) = 1024 MB

1 MB (Mega Byte) = 1024 KB

1 KB (Kilo Byte) = 1024 Bytes

1 Byte = 8 Bit

Hence, largest unit of information is TB (Tera Byte) and smallest unit of information is Bit.

Word and WordPad can save documents as ASCII text and HTML, but this approach can lead to problems. NotePad should launch with a new document open.

From the File pull-down menu, Select "Save As," save the file to the Desktop, and name the file using the ".html" extension (e.g., "home.html").

In SQL, BETWEEN Keyword is used for ranges like Number Ranges, Date Ranges, etc...

We can make an equation:

3(100000 + x) = 10x+1

(Why? Well, adding 100000 puts a 1 at the front of a five-digit number, and multiplying by 10 and adding 1 puts a 1 at the end of a number)

Solving this gives:

10x+1 = 3(100000 + x)
10x+1 = 300000 + 3x
10x = 299999 + 3x
7x = 299999
x = 299999/7 = 42857

The answer is 42857 (142857 is three times smaller than 428571).

This is a common error while compiling C program in Linux. This error occurs when you are using pthread_create function to create threads in your programs.

To fix this problem ensure following points:
Include header file pthread.h in your program.
Add –lpthread linker flag with compilation command.
1- Include Header file
#include <stdio.h>
#include <pthread.h>
...
...
2- Compile command
gcc main.c -o main -lpthread

• An Interpreter is a program that reads in as input a source program, along with data for the program, and translates the source program step by step.

The Java interpreter decodes each lines bytecode and runs a series of machine instructions for that bytecode. The JVM takes the byte code and generates machine code. The byte code is compiled to machine code, and the machine code is executed.

Let the smaller number be k.
Then, larger number = (3355 + k)
Therefore 3355 + k = (6k + 15)
‹=› 5k = 3340
‹=› k = 668.

Therefore, the smaller number k = 668 and now the larger number = 3355+668 = 4023.