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Q:

A sum of money invested at compound interest amounts to Rs. 800 in 3 years and to Rs. 840 in 4 years. The rate of interest per annum is

A) 6% B) 4%
C) 5% D) 7%
 
Answer & Explanation Answer: C) 5%

Explanation:

S.I. on Rs.800 for 1 year

=Rs[840 - 800]

= Rs.40

 

Rate

=(100x40/800x1)%

= 5%

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

The difference between simple interest and compound interest on Rs. 1200 for one year at 10% per annum reckoned half yearly is

A) Rs.2.50 B) Rs.3
C) Rs.4 D) Rs.4.50
 
Answer & Explanation Answer: B) Rs.3

Explanation:

S.I

= Rs.(1200x10x1/100)

= Rs.120.

 

C.I

= Rs[(1200x1+5/100)² -1200]

= Rs.123. 

 

Difference

= Rs.[123-120]

= Rs. 3.

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Filed Under: Compound Interest
Exam Prep: GRE

Q:

On a sum of money, the simple interest for 2 years is Rs. 660,while the compound interest is Rs.696.30,the rate of interest being the same in both the cases. The rate of interest is

A) 10% B) 11%
C) 12% D) 13%
 
Answer & Explanation Answer: B) 11%

Explanation:

Difference in C.I and S.I for 2 years

= Rs(696.30-660)

=Rs. 36.30.

 

S.I for one years = Rs330.

S.I on Rs.330 for 1 year =Rs. 36.30 

 

Rate

= (100x36.30/330x1)%

= 11%

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

What is the output of this program ?

class main_arguments {
            public static void main(String [ ] args)
            {
                String [][] argument = new String[2][2];
                int x;
                argument[0] = args;
                x = argument[0].length;
                for (int y = 0; y < x; y++)
                    System.out.print(" " + argument[0][y]);           
            }
        }

A) 1 1 B) 1 0
C) 1 0 3 D) 1 2 3
 
Answer & Explanation Answer: D) 1 2 3

Explanation:

In argument[0] = args;, the reference variable arg[0], which was referring to an array with two elements, is reassigned to an array (args) with three elements.
Output:
$ javac main_arguments.java
$ java main_arguments
1 2 3

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Filed Under: Java
Exam Prep: GATE

Q:

Two electric bulbs marked 25W – 220V and 100W – 220V are connected in series to a 440Vsupply. Which of the bulbs will fuse?

A) 25 W B) Both
C) 100 W D) Neither
 
Answer & Explanation Answer: A) 25 W

Explanation:

Resistances of both the bulbs are

 

R1=V^2/P1 = 220^2/25

 

R2 = V^2/P2 = 220^2/100

 

Hence  R1gt ; R2

 

When connected in series, the voltages divide in them in the ratio of their resistances. The voltage of 440 V devides in such a way that voltage across 25 w bulb will be more than 220 V. Hence 25 w bulb will fuse.

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Filed Under: Physics
Exam Prep: AIEEE

Q:

#define clrscr() 100

main()

{

clrscr();

printf( "%dn", clrscr() );

}

A) 100 B) 0
C) Compilation error D) Exception occurs
 
Answer & Explanation Answer: A) 100

Explanation:

Preprocessor executes as a seperate pass before the execution of the compiler. So textual replacement of clrscr() to 100 occurs.The input program to compiler looks like this :

main ()

{

100;

printf("%d\n",100);

}

Note: 100; is an executable statement but with no action. So it doesn't give any problem.

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Filed Under: Programming

Q:

Albert invested an amount of Rs.8000 in a fixed deposit scheme for 2 years at compound interest rate 5 p.c.p.a. How much amount will Albert get on maturity of the fixed deposit ?

A) Rs.8600 B) Rs.8830
C) Rs.8500 D) Rs.8820
 
Answer & Explanation Answer: D) Rs.8820

Explanation:

Amount

=Rs.[8000x(1+5/100)²]

= Rs.[8000 x 21/20x21/20]

= Rs.8820. 

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

In the match between India and Pakistan at Jaipur on 02-10-1983, which new rule was introduced

A) Limit of overs wes reduced to 50 overs B) The rule of field restriction was taken
C) over throw runs were batsmans score D) Noballs & wides were debited to bowlers analysis
 
Answer & Explanation Answer: D) Noballs & wides were debited to bowlers analysis

Explanation:
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Filed Under: Sports