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Q:

When 0.232323.... is converted into a fraction , then the result is 

 

A) 1/5 B) 2/9
C) 23/99 D) 23/100
 
Answer & Explanation Answer: C) 23/99

Explanation:

0.232323...=0.23 =2399

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Filed Under: Decimal Fractions

Q:

What is the difference between the biggest and the smallest fraction among 2/3 , 3/4 , 4/5 and 5/6?

A) 1/6 B) 1/12
C) 1/20 D) 1/30
 
Answer & Explanation Answer: A) 1/6

Explanation:

Converting each of the given fractions into decimal form, we get

2/3 = 0.66, 3/4 = 0.75, 4/5 = 0.8, 5/6 = 0.833 

Since 0.833>0.8>0.75>0.66 

So, 5/6 > 4/5 > 3/4 > 2/3 

Therefore,  Required Difference = 5/6 - 2/3 = 1/6

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Filed Under: Decimal Fractions

Q:

A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the begining and 100 more  after 35 days and completes the work in stipulated time. If he had not  engaged  the additional men, how many days  behind schedule would it be finished?

A) 3 B) 5
C) 6 D) 9
 
Answer & Explanation Answer: B) 5

Explanation:

[(100 x 35) + (200 x 5)]men can finish the work in 1 day 

Therefore, 4500 men can finish the work in 1 day. 100 men can finish it in  4500/100= 45 days.

This is 5 days behind Schedule

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Filed Under: Chain Rule

Q:

Arjun and Bhishma are running on a circular track of length 600m. Speed of Arjun is 30 m/s and that of Bhishma is 20 m/s .They start fro the same point at the same time in the same direction. When will they meet again for the first time?

Answer

SolTime = Circumference Relative Speed = 60010 = 60 sec.


 


Actually Arjun has to make a lead of 600 m, because when Arjun will be 600m ahead of Bhishma, they will be together again as a person when completes the total length it starts retracing he same path and thus Arjun and Bhishma can be together again.


 


Since , they make  a difference of 10 m in 1 second. so, he will create 600m difference in 60 second.

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Subject: Time and Distance Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

Q:

In a one km race A gives B a start of 100m and in a one km race B gives a start of 80 m to C. In a 1 km race who will win and by how much distance from the worst performer between two losers?

Answer

Ratio  of speeds of A:B = 1000:900 = 100:90


Ratio of speeds of B:C = 1000:920 = 100:92


Therefore, when A moves 1000m , B moves 900 m and when B moves 900m, C moves 828m


Thus,             


Since , C moves 8 % less than B in the same time . Thus, C is the worst performer and A will win by him by 172 m

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Q:

A contractor  undertook a project to complete it in 20 days which needed 5 workers to work continuously for all the days estimated. But before the start of the work the client wanted to complete it earlier than the scheduled time, so the contractor calculated that  he needed to increase 5 additional  men every 2 days to complete the work in the time the client wanted it:

If the work was further increased by 50% but the contractor continues to increase the 5 workers o every 2 days then how many more days are required over the initial time specified by the  client.

A) 1 day B) 2 days
C) 5 days D) None of these
 
Answer & Explanation Answer: B) 2 days

Explanation:

Total work = 100+50 = 150man-days

In 8 days 100 man-days work  has been completed. Now on 9th and 10th day there will be 25 workers. So in 2 days they wll complete additional 50 man- days work. Thus the work requires 2 more days.

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Filed Under: Time and Work

Q:

A Contractor employed a certain number of workers  to finish constructing a road in a certain scheduled time. Sometime later, when a part of work had been completed, he realised that the work would get delayed by three-fourth of the  scheduled time, so he at once doubled the no of workers and thus he managed to finish the road on the scheduled time. How much work he had been completed, before increasing the number of workers?

A) 10 % B) 14 ( 2/7 )%
C) 20 % D) Can't be determined
 
Answer & Explanation Answer: B) 14 ( 2/7 )%

Explanation:

Let he initially employed x workers which works for D days and he estimated 100 days for the whole work and then he doubled the worker for (100-D) days.

D * x +(100- D) * 2x= 175x 

=>  D= 25 days 

Now , the work done in 25 days = 25x 

Total work = 175x

Therefore, workdone before increasing the no of workers = 25x175x×100 % = 1427%

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Filed Under: Time and Work

Q:

The Committee has criticized the Institute for its failure to implement a dozen of regular programmes despite an increase in the staff strength and not drawing up a firm action plan for studies and research.

 

Courses of Action:

I.The broad objectives of the Institute should be redefined to implement a practical action plan.

II.The Institute should give a report on reasons for not having implemented the planned programmes.

A) Only I follows B) Only II follows
C) Neither I nor II follows D) Both I and II follow
 
Answer & Explanation Answer: D) Both I and II follow

Explanation:

The problem is that despite an increase in staff strength, the Institute has failed in its objective of implementing its plan. So, either there should be reasons for the lackening or the plans are a failure and must be revised for practical implementation. Thus, both the courses follow.

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