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Q:

Study the pie - chart carefully to answer the questions below :

The Pie chart shows the percentage quantity of fruits at two fruit shops A and B

1. What is the difference between the quantity of Guava at Shop B and that at Shop A ?

1. 40 Kg 2. 45 kg 3. 35 kg 4. 30 kg 5. 50 kg

2. If the price of Mango is Rs. 30 per kg, Apple Rs.40 per kg and orange Rs.20 per kg, then what is the ratio of their costs at Shop A?

1. 1 : 4 : 6 2. 9 : 8 : 5 3. 3 : 7 : 8 4. 5 : 4 : 1 5. 2 : 5 : 7

3. The quantity of Mango at Shop B is what per cent of the quantity of Mango at Shop A ?

1. 20% 2. 220% 3. 120% 4. 80% 5. 180%

4. If the price of Mango is Rs.30 per kg, Apple Rs. 40 per kg, orange Rs.20 per kg, Other fruits Rs.15 per kg and Guava Rs. 18 per kg for both Shop A and B, then what is the difference between the cost of all fruits at Shop A and that at Shop B ?

1. Rs.7200 2. Rs.3500 3. Rs. 6400 4. Rs.5100 5. Rs.4600

5. The quantity of Orange at Shop A is what percent more than that of Apple at Shop B ?

1. 161.52% 2. 195.5% 3. 182% 4. 190% 5. 171.42%

Answer

1. Answer : 1

Explanation : Quantity of Guava at Shop A = $1200 \times \frac{10}{100}$ = 120 kg

Quantity of Guava at Shop B = $1000 \times \frac{16}{100}$ = 160 kg

Therefore, Required difference = 160 - 120 = 40 kg

2. Answer : 2

Explanation : Cost of Mango at Shop A = $30 \times 1200 \times \frac{24}{100}$ = Rs. 8640

Cost of Apple = $40 \times 1200 \times \frac{16}{100}$ = Rs. 7680

Cost of Orange = $20 \times 1200 \times \frac{20}{100}$ = Rs.4800

Therefore, Required Ratio = 8640 : 6780 : 4800 = 9 : 8 : 5

3. Answer : 3

Explanation : Quantity of Mango at Shop B = $1000 \times \frac{24}{100}$ = 240 kg

Quantity of Mango at Shop A = $1200 \times \frac{24}{100}$ = 288 kg

Therefore, Req % = $288 \times \frac{100}{240}$ = 120% of the quantity of Mango at Shop A

4. Answer : 4

Explanation : Cost of total fruits at Shop A = Cost of Mango + Cost of Apple + Cost of Guava + Cost of orange + Cost of other fruits

= $1200 \times \frac{24}{100} \times 30 + 1200 \times \frac{16}{100} \times 40 + 1200 \times \frac{10}{100} \times 18 + 1200 \times \frac{20}{100} \times 20 + 1200 \times \frac{30}{100} \times 15$

= Rs. 28680

Cost of Total Fruits at Shop B

= $1000 \times \frac{24}{100} \times 30 + 1000 \times \frac{14}{100} \times 40 + 1000 \times \frac{16}{100} \times 18 + 1000 \times \frac{20}{100} \times 20 + 1000 \times \frac{26}{100} \times 15$

= 7200 + 5600 + 2880 + 4000 + 3900

= Rs. 23580

Therefore, Req.difference = 28680 - 23580 = Rs.5100

5. Answer : 5

Explanation: Quantity of Orange at Shop A = $1200 \times \frac{20}{100}$ = 240 kg

Quantity of Apple at Shop B = $1000 \times \frac{14}{100}$ = 140 kg

Therefore, Req % = $\frac{240 \times 100}{140}$ = 171.42% more than the quantity of Apple at Shop B.

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Subject: Pie Charts

Q:

Determine the number of rectangles and hexagons in the following figure.

A) 30, 5	B) 32, 3
C) 28, 5	D) 30, 3

Answer & Explanation Answer: A) 30, 5

Explanation:

The figure may be labelled as shown

Rectangles :

The simplest rectangles are CVSR, VETS, RSWM and STKW i.e 4 in number.

The rectangles composed of two components each are CETR, VEKW, RTKM and CVWM i.e 4 in number.

The rectangles composed of three components each are ACRP, PRMO, EGHT and THIK i.e 4 in number.

The rectangles composed of four components each are CEKM, AVSP, PSWO,VGHS and SHIW i.e 5 in number.

The rectangles composed of five components each are AETP, PTKO, CGHR and RHIM i.e 4 in number.

The rectangles composed of six components each are ACMO and EGIK i.e 2 in number.

The rectangles composed of eight components each are AGHP, PHIO, AVWO and VGIW i.e 4 in number.

The rectangles composed of ten components each are AEKO and CGIM i.e 2 in number.

AGIO is the only rectangle having sixteen components

Total number of rectangles in the given figure = 4 + 4 + 4 + 5 + 4 + 2 + 4 + 2 + 1 = 30.

Hexagons :

The hexagons in the given figure are CDEKLM, CEUKMQ, CFHJMQ, BEUKNP and BFHJNP. So, there are 5 hexagons in the given figure.

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Filed Under: Analytical Reasoning
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

Q:

Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages?

Answer

Let A's age 10 years ago be x years . Then B's age 10 years ago be 2x years

$\Rightarrow \frac{x+10}{2x+10}=\frac{3}{4}$

$\Rightarrow4(x+10)=3(2x+10)$

$\Rightarrow x=5$

$\therefore$ Total of their present ages = x + 10 + 2x + 10

= 3x+20

= 3 * 5 + 20 = 35 years

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Subject: Problems on Ages

Q:

8 years ago Ramana's mother was five times older than her daughter. After 8 years the mother will be twice older than her daughter. Find the present age of Ramana?

Answer

Let Ramana's age 8 years ago be x years and mother's age 8 years ago be 5x

$\Rightarrow$ 2(x + 16) = 5x + 16

$\Rightarrow$ 2x + 32 = 5x + 16

$\Rightarrow$ 3x = 16

$\Rightarrow$ $x=\frac{16}{3}$ years

Hence, Present age of Ramana = $x+8=\frac{16}{3}+8=\frac{40}{3}=13\frac{1}{3}$ years

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Subject: Problems on Ages

Q:

The ratio of the present ages of P and Q is 3 : 4. Five years ago, the ratio of their ages was 5 : 7. Find their present ages.

Answer

As the ratio of their present ages is 3 : 4 , let their present ages be 3X and 4X.

So, 5 years ago, as the ratio of their ages was 5 : 7, we can write (3x-5) : (4x-5) = 5 : 7. Solving, we get X = 10. Hence, their present ages are 3X = 30 and 4X = 40

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Subject: Problems on Ages

Q:

A woman going with a boy is asked by another woman about their relationship between them. The woman replied, "My maternal Uncle and the uncle of his maternal uncle is the same". How is the lady related with that boy?

A) Grandmother and Grandson	B) Mother and Son
C) Aunt and Nephew	D) None of these

Answer & Explanation Answer: C) Aunt and Nephew

Explanation:

Clearly, the brother of woman's mother is the same as the brother of the father of boy's maternal uncle. So, the woman's mother's brother is the boy's maternal uncle's father. Thus the woman's mother's brother's son is boy's maternal uncle, i.e woman's mother's brother's daughter is boy's mother.

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Filed Under: Blood Relations

Q:

A cyclist leans inwards when he is negotiating a curve so that

A) he may increase his speed	B) his weight may be reduced
C) necessary centripetal force may be available from the horizontal component of the normal reaction due to the track to maintain the curved motion.	D) no frictional force may be produced between the wheels and the axle

Answer & Explanation Answer: C) necessary centripetal force may be available from the horizontal component of the normal reaction due to the track to maintain the curved motion.

Explanation:

No circular or curved motion is possible without providing the necessary centripetal force. (C) provides this and so is the answer.

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Filed Under: Physics

Q:

How do you go about making an important decision affecting your career?

Answer

Career decisions are surely the toughest one and almost inevitable. I follow my instincts during any doubtful situations. b'coz in dilema u r not in the position to make a decision. what better guide can we get, other then our inner voice, during those difficult situations. This doesn't infact means that decision regarding the priority in life be left just to intuitions. Intuitions also needs input in the form of one's likes and dislikes. Goals proper set once, as such, go a long way in creating a good intuitive judgement.

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Subject: Decisiveness

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