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Q:

Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:

A) 9	B) 9.6
C) 10	D) 10.8

Answer & Explanation Answer: D) 10.8

Explanation:

Relative speed = (60 + 40) km/hr =[ 100 x ( 5 / 18 ) ]m/sec = ( 250 /9 ) m/sec.
Distance covered in crossing each other = (140 + 160) m = 300 m.
Required time = [ 300 x ( 9/250 ) ] sec = ( 54/ 5 )sec = 10.8 sec.

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Filed Under: Problems on Trains

Q:

A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train ?

A) 230 m	B) 240 m
C) 260 m	D) 320 m

Answer & Explanation Answer: A) 230 m

Explanation:

Relative speed = (120 + 80) km/hr

=(200*5/18)m/s = (500/9)m/s

Let the length of the other train be x metres.

Then, x+270/9 = 500/9

=> x + 270 = 500

=> x = 230.

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Q:

0.1 decates ago, Vijaya was quadrice as old as her daughter Simran. 0.6 decades hence, Vijaya’s age will beat her daughter’s age by 0.9 decades. The proportion of the current ages of Vijaya and Simran is : [ 0.1 Decates =1 Year; quadrice = 4 times]

A) 8:1	B) 10:2
C) 11:4	D) 13:4

Answer & Explanation Answer: D) 13:4

Explanation:

Let, Ages of Vijaya and Simran – 1 year ago was 4A and A years correspondingly.
Then, [(4A + 1) + 6] – [(A + 1) + 6] = 9
3A = 9 => A = 3

Needed Ratio = (4A + 1) : (A + 1) = 13 : 4

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Filed Under: Problems on Ages

Q:

If two times of the daughter’s age in years is included to the mother’s age, the total is 70 and if two times of the mother’s age is included to the daughter’s age, the total is 95. So the Mother’s age is,

A) 30	B) 38
C) 40	D) 41

Answer & Explanation Answer: C) 40

Explanation:

Let daughter’s age = A and mother’s age = B
Given: 2A+B = 70 and A+2B = 95
Solving B, we will get B = 40.

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Filed Under: Problems on Ages

Q:

Melt : Liquid :: Freeze : ?

A) Condense	B) Solid
C) Ice	D) Crystal

Answer & Explanation Answer: B) Solid

Explanation:

Here the relation in the given words is, First is the process of formation of the second.

That is, when anything melts, it forms liquid. Similarly, when anything freezes it forms solid.

Hence, Melt : Liquid :: Freeze : Solid.

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Filed Under: Analogy
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Q:

A man’s current age is $\frac{2}{5}$ of the age of his father. After 8 years, he will be $\frac{1}{2}$ of the age of his father. What is the age of father at now ?

A) 50	B) 40
C) 33	D) 30

Answer & Explanation Answer: B) 40

Explanation:

Let, father’s current age is A years.
Then, Man’s current age = $[(\frac{2}{5} * A)]$ years.

$[(\frac{2}{5} * A)]$ +8= $(\frac{1}{2}) (A + 8)$

2(2A+40) = 5(A+8)

A = 40

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Filed Under: Problems on Ages

Q:

Proportion of Yuvaraj’s age to Ganguly’s age is 4:3. Yuvaraj willl be 26 years old after 6 years. What is the age of Ganguly now ?

A) 17 years	B) 15 years
C) 19 years	D) 12 years

Answer & Explanation Answer: B) 15 years

Explanation:

Current ages of Yuvaraj = 4A and Ganguly = 3A
So that 4A + 6 = 26
A = 5
Current age of Ganguly = 3A
=> 3 x 5 = 15 years

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Filed Under: Problems on Ages

Q:

The ages of Krish and Vaibhav are in the proportion of 3 : 5. After 9 years, the proportion of their ages will be 3 : 4. Then the current age of Vaibhav is:

A) 10	B) 13
C) 15	D) 18

Answer & Explanation Answer: C) 15

Explanation:

Krish’s age = 3A and Vaibhav’s age = 5A

(3A+9)/(5A+9) = 3/4

=> 4 (3A + 9) = 3 (5A + 9)

=> A = 3

Therefore, Vaibhav’s age = 15 years.

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Filed Under: Problems on Ages

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