Find the number of triangles in the given figure?
We may label the figure as shown.
The Simplest triangles are AFB, FEB, EBC, DEC, DFB and AFD i.e 6 in number.
The triangles composed of two components each are AEB, FBC, DFC, ADE, DBE and ABD i.e 6 in number.
The triangles composed of three components each are ADC and ABC i.e 2 in number.
There is only one triangle i.e DBC which is composed of four components.
Thus, there are 6 + 6 + 2 + 1 = 15 triangles in the figure
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What is the number of rectangles in the following figure?
The simplest rectangles are AEHG, EFJH, FBKJ, JKCL and GILD i.e 5 in number.
The rectangles composed of two components each are AFJG and FBCL i.e 2 in number
Only one rectangle namely AFLD is composed of three components and only one rectangle namely ABCD is composed of five components.
Thus, there are 5 + 2 + 1 + 1 = 9 rectangles in the given figure.
Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages?
Let A's age 10 years ago be x years . Then B's age 10 years ago be 2x years
Total of their present ages = x + 10 + 2x + 10
= 3x+20
= 3 * 5 + 20 = 35 years
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The ratio of the father's age to the son's age is 3 : 1. The product of their ages is 147. The ratio of their ages after 5 years will be?
Let father's age be 3x and son's age be x years
Father's age after 5 years = 3x + 5 = 26 years
Son's age after 5 years = x + 5 = 12 years
Ratio of father's and son's ages = 26 : 12 = 13 : 6
The ratio of the present ages of P and Q is 3 : 4. Five years ago, the ratio of their ages was 5 : 7. Find their present ages.
As the ratio of their present ages is 3 : 4 , let their present ages be 3X and 4X.
So, 5 years ago, as the ratio of their ages was 5 : 7, we can write (3x-5) : (4x-5) = 5 : 7. Solving, we get X = 10. Hence, their present ages are 3X = 30 and 4X = 40
Arrange the following in a logical order :
1. Shoulder 2. Wrist 3. Elbow 4. Palm 5. Finger
Clearly, Here are the names of parts of a hand, Which may be arranged
(i) from top to bottom, i.e, Shoulder, Elbow, Wrist, Palm, Finger - Which is 1, 3, 2, 4, 5 (or)
(ii) from bottom to top, i.e, Finger, Palm, Wrist, Elbow, Shoulder - Which is 5, 4, 2, 3, 1
Out of these, the sequence 5, 4, 2, 3, 1 is given in the alternatives provided. Hence, the answer is (D).
1. Euphoria 2. Happiness 3. Ambivalence 4. Ecstasy 5. Pleasure
All the given words stand for 'Joy', but the intensity increases in the order - Ambivalence, Happiness, Pleasure, Euphoria, Ecstasy.
Thus the correct order is 3, 2, 5, 1, 4.
Hence the answer is (C)
CK169JROS2419TXKM??PV
Putting A=1, B=2, C=3,..., M=13,....,X=24,Y=25, Z=26, we have :
JR = J + R2 + 2 = 10 + 18 2 + 2 = 16
CK = C + K2 + 2 = 3 + 112 + 2 = 9
TX = T + X2+ 2 = 20 + 242 + 2 = 24
OS = O + S2 + 2 = 15 + 192 + 2 = 19
So, the missing numbers are :
21 and 14
Hence, the answer is (b).