A) 36 kmph | B) 32 kmph |

C) 29 kmph | D) 24 kmph |

Explanation:

Let the speed of the train be 'S' kmph

From the given data,

Distance = Length of train = D = 200 mts = 200 x 18/5 kms

Time = 10 sec

given speed of the motorcycler = 12 kmph

Relative speed as they are moving in the same direction = (S - 12) kmph

$\mathbf{(}\mathbf{S}\mathbf{-\; 12)}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{200}\mathbf{}\mathbf{x}\mathbf{}{\displaystyle \frac{\mathbf{18}}{\mathbf{5}}}}{\mathbf{15}}\phantom{\rule{0ex}{0ex}}\mathbf{S}\mathbf{}\mathbf{-}\mathbf{}\mathbf{12}\mathbf{}\mathbf{=}\mathbf{}\mathbf{48}\phantom{\rule{0ex}{0ex}}\mathbf{S}\mathbf{}\mathbf{=}\mathbf{}\mathbf{60}\mathbf{}\mathbf{kmph}\phantom{\rule{0ex}{0ex}}$

Hence, the speed of the train = **S = 60 kmph**

Now,

Let the speed of the jeep be** 'x'** kmph

$\mathbf{60}\mathbf{}\mathbf{-}\mathbf{}\mathbf{x}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{200}\mathbf{}\mathbf{x}\mathbf{}{\displaystyle \frac{\mathbf{18}}{\mathbf{5}}}}{\mathbf{20}}\phantom{\rule{0ex}{0ex}}\mathbf{60}\mathbf{}\mathbf{-}\mathbf{}\mathbf{x}\mathbf{}\mathbf{=}\mathbf{}\mathbf{36}\phantom{\rule{0ex}{0ex}}\mathbf{x}\mathbf{}\mathbf{=}\mathbf{}\mathbf{60}\mathbf{}\mathbf{-}\mathbf{}\mathbf{36}\phantom{\rule{0ex}{0ex}}\mathbf{x}\mathbf{}\mathbf{=}\mathbf{}\mathbf{24}\mathbf{}\mathbf{kmph}$

Therefore, the speed of the jeep =** x = 24 kmph.**

A) 6 km | B) 16.5 km |

C) 8 km | D) 10km |

A) 51 sec | B) 0.51 min |

C) 5.1 sec | D) 5.1 min |

A) 35 km | B) 32 km |

C) 33 km | D) 36 km |

A) 90 km | B) 67.5 km |

C) 13.5 km | D) 75.5 km |

A) 17.6 km | B) 17.2 km |

C) 16.4 km | D) 16.8 km |

A) 11 km | B) 10 km |

C) 13 km | D) 12 km |