What least number must be subtracted from 13601, so that the remainder is divisible by 87 ?

A) 23 | B) 31 |

C) 29 | D) 37 |

Explanation:

87)13601(156

87

-----

490

435

-----

551

522

-----

29

-----

Required number is 29.

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Subject: Numbers - Quantitative Aptitude - Arithmetic Ability(51 + 52 + 53 + .........+100) is equal to

51 + 52 + 53 + ...........+ 100

= (1 + 2 + 3 + .... + 100) - (! + 2 + 3 + ...... + 50)

=

= (5050 - 1275) = 3775

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Subject: Numbers - Quantitative Aptitude - Arithmetic Ability

A number when divided by 296 leaves 75 as remainder.When the same number is divided by 37,the remainder will be:

A) 1 | B) 3 |

C) 5 | D) 2 |

Explanation:

Let the Number be Y.

Then Y = 296 q + 75

= (37 x 8)q +( 37 x 2) + 1

= 37 (8q + 2) + 1

Thus, when the number is divided by 37, the remainder is 1

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Subject: Numbers - Quantitative Aptitude - Arithmetic Ability

The sum of all two digit numbers divisible by 5 is

A) 945 | B) 678 |

C) 439 | D) 568 |

Explanation:

Required numbers are 10,15,20,25,...,95

This is an A.P. in which a=10,d=5 and l=95.

Let the number of terms in it be n.Then t=95

So a+(n-1)d=95.

10+(n-1)*5=95,then n=18.

Required sum=n/2(a+l)=18/2(10+95)=945.

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Subject: Numbers - Quantitative Aptitude - Arithmetic Ability

The difference between a positive proper fraction and its reciprocal is 9 / 20. Then the fraction is :

A) 3/5 | B) 3/10 |

C) 4/5 | D) 5/4 |

Explanation:

Let the required fraction be x. Then, (1 / x )- x = 9/20

1 - x^(2) / x = 9 / 20 => 20 - 20 * x^(2) = 9 * x.

20 * x^(2) + 9 *x - 20 = 0.

=> (4 * x + 5) (5 * x - 4) = 0.

=> x = 4 / 5.

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Subject: Numbers - Quantitative Aptitude - Arithmetic Ability