## Numbers

Quantitative aptitude questions are asked in many competitive exams and placement exam. ' Numbers ' is a category in Quantitative Aptitude. Quantitative aptitude questions given here are extremely useful for all kind of competitive exams like Common Aptitude Test (CAT), MAT, GMAT, IBPS Exam, CSAT, CLAT, Bank Competitive Exams, ICET, UPSC Competitive Exams, CLAT, SSC Competitive Exams, SNAP Test, KPSC, XAT, GRE, Defense Competitive Exams, L.I.C/ G. I.C Competitive Exams, Railway Competitive Exam, TNPSC, University Grants Commission (UGC), Career Aptitude Test (IT Companies) and etc., Government Exams etc.

We have a large database of problems on " Numbers " answered with explanation. These will help students who are preparing for all types of competitive examinations.

What least number must be subtracted from 13601, so that the remainder is divisible by 87 ?

 A) 23 B) 31 C) 29 D) 37

Explanation:

87)13601(156
87
-----
490
435
-----
551
522
-----
29
-----
Required number is 29.

Subject: Numbers - Quantitative Aptitude - Arithmetic Ability

27

(51 + 52 + 53 + .........+100) is equal to

51 + 52 + 53 + ...........+ 100

= (1 + 2 + 3 + .... + 100) - (! + 2 + 3 + ...... + 50)

=$\inline \fn_jvn \left ( \frac{100\times 101}{2}-\frac{50\times 51}{2} \right )$

=  (5050 - 1275) = 3775

Subject: Numbers - Quantitative Aptitude - Arithmetic Ability

31

A number when divided by 296 leaves 75 as remainder.When the same number is divided by 37,the remainder will be:

 A) 1 B) 3 C) 5 D) 2

Explanation:

Let the Number be Y.

Then  Y = 296 q + 75

= (37 x 8)q +( 37 x 2) + 1

= 37 (8q + 2) + 1

Thus, when the number is divided by 37, the remainder is 1

Subject: Numbers - Quantitative Aptitude - Arithmetic Ability

17

The sum of all two digit numbers divisible by 5 is

 A) 945 B) 678 C) 439 D) 568

Explanation:

Required numbers are 10,15,20,25,...,95
This is an A.P. in which a=10,d=5 and l=95.
Let the number of terms in it be n.Then t=95
So a+(n-1)d=95.
10+(n-1)*5=95,then n=18.
Required sum=n/2(a+l)=18/2(10+95)=945.

Subject: Numbers - Quantitative Aptitude - Arithmetic Ability

4

The difference between a positive proper fraction and its reciprocal is 9 / 20. Then the fraction is :

 A) 3/5 B) 3/10 C) 4/5 D) 5/4

Explanation:

Let the required fraction be x. Then, (1 / x )- x = 9/20
1 - x^(2) / x = 9 / 20  =>  20 - 20 * x^(2) = 9 * x.
20 * x^(2) + 9 *x - 20 = 0.
=> (4 * x + 5) (5 * x - 4) = 0.
=> x = 4 / 5.