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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 614 p.a for 2 years. Find his gain in the transaction per year

A) Rs. 112.50 B) Rs.150.25
C) Rs.167.50 D) Rs.170
 
Answer & Explanation Answer: A) Rs. 112.50

Explanation:

 gain in 2 years =Rs.5000*254*2100-5000*4*2100  

= Rs. (625 - 400) 

= Rs. 225 

 gain in 1 year =Rs.2252=112.50

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

124 44142
Q:

In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by

A) 21 m B) 26 m
C) 28m D) 29m
 
Answer & Explanation Answer: C) 28m

Explanation:

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Filed Under: Races and Games

41 44129
Q:

Calculate the area (in sq.cm) of a circle whose diameter is 35 cm.

 

A) 1925 B) 962.5
C) 857.5 D) 1715
 
Answer & Explanation Answer: B) 962.5

Explanation:
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Filed Under: Area
Exam Prep: Bank Exams

0 44113
Q:

In the following question, select the missing number from the given series.


1, 3, 5, 7, ?

 

A) 9 B) 11
C) 10 D) 12
 
Answer & Explanation Answer: A) 9

Explanation:
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Filed Under: Number Series
Exam Prep: Bank Exams

49 44111
Q:

Select the related word/letters/number from the given alternatives.

ET : VG : : NO : ?

A) IM B) MI
C) ML D) LM
 
Answer & Explanation Answer: C) ML

Explanation:
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Filed Under: Analogy
Exam Prep: AIEEE , Bank Exams , CAT

0 44105
Q:

In a two-digit number, the digit in the unit's place is more than twice the digit in ten's place by 1. If the digits in the unit's place and the ten's place are interchanged,difference between the newly formed number and the oiginal number is less than the original number by 1. What is the original number ?

A) 35 B) 36
C) 37 D) 39
 
Answer & Explanation Answer: C) 37

Explanation:

Let the ten's digit be x. Then, unit's digit = 2x + 1.

[10x + (2x + 1)] - [{10 (2x + 1) + x} - {10x + (2x + 1)}] = 1

<=> (12x + 1) - (9x + 9) = 1 <=> 3x = 9, x =  3.

So, ten's digit = 3 and unit's digit = 7. Hence, original number = 37.

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Filed Under: Problems on Numbers

58 44103
Q:

The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

A) 20 B) 200
C) 300 D) 400
 
Answer & Explanation Answer: B) 200

Explanation:

Let length of plot = L meters, then breadth = L - 20 meters

and perimeter = 2[L + L - 20] = [4L - 40] meters

[4L - 40]  * 26.50 = 5300

[4L - 40] = 5300 / 26.50 = 200

4L = 240

L = 240/4= 60 meters. 

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

30 44090
Q:

After replacing an old member by a new member, it was found that the average age of five members of a club is the same as it was 3 years ago. What is the difference between the ages of the replaced and the new member ?

A) 12 B) 13
C) 14 D) 15
 
Answer & Explanation Answer: D) 15

Explanation:

i) Let the ages of the five members at present be a, b, c, d & e years. 

And the age of the new member be f years. 

ii) So the new average of five members' age = (a + b + c + d + f)/5 ------- (1) 

iii) Their corresponding ages 3 years ago = (a-3), (b-3), (c-3), (d-3) & (e-3) years 

So their average age 3 years ago = (a + b + c + d + e - 15)/5 = x ----- (2) 

==> a + b + c + d + e = 5x + 15 

==> a + b + c + d = 5x + 15 - e ------ (3) 

iv) Substituting this value of a + b + c + d = 5x + 15 - e in (1) above, 

The new average is: (5x + 15 - e + f)/5 

Equating this to the average age of x years, 3 yrs, ago as in (2) above, 

(5x + 15 - e + f)/5 = x 

==> (5x + 15 - e + f) = 5x 

Solving e - f = 15 years. 

Thus the difference of ages between replaced and new member = 15 years.

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Filed Under: Average

165 44059