Aptitude and Reasoning Questions

Q:

A and B enter into partnership. A supplies whole of the capital amounting to Rs. 45000 with the condition that the profits to be equally divided and that B pays A interest on half of the capital at 10% per annum, but receives Rs. 120 per month for carrying on the concern.Find their total yearly profit when B's income is one half of A's income.

Answer

Let the total profit be Rs. x


Amount paid to B as salary = (120 x 12)


                                       = Rs.1440


Share of each = \inline (\frac{x-1440}{2})


Interest paid by B = \inline \frac{22500\times 10}{100}=Rs.2250


Total money received by  A = \inline \frac{x-1440}{2}+2250


                                       = Rs.\inline (\frac{x+3060}{2})


Total money received by B


\inline [(\frac{x-1440}{2})+1440-2250]= (\frac{x-3060}{2})


\inline \Rightarrow \frac{1}{2}-(\frac{x+3060}{2})-(\frac{x-3060}{2})


\inline \Rightarrow x=9180 

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Subject: Partnership

60 26571
Q:

The ratio of water and alcohol in two different containers is 2:3 and 4:5. In what ratio we are required to mix the mixtures  of two containers in order to get the new mixture in which the ratio of alcohol and water be 7:5?

A) 7:3 B) 5:3
C) 8:5 D) 2:7
 
Answer & Explanation Answer: B) 5:3

Explanation:

W1:A1  W2:A2  ..... WN:AN

  2 : 3                   4 : 5                    5 : 7 

 

W1W1+A1 = 25 W2W2+A2=49  WNWN+AN = 512

= 72/180

= 80/180

= 75/180  

                     

 

 =>     5   :   3

 

Therefore, the ratio is  5: 3

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Filed Under: Alligation or Mixture
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

49 26557
Q:

In a certain coding language, iF GO = 32 & SHE = 49 then SOME will be equal to ?

A) 56 B) 58
C) 62 D) 64
 
Answer & Explanation Answer: A) 56

Explanation:

If we count letters till the end of the alphabet including that letter in reverse order then
Here the values are nothing but the values corresponding to the alphabets when taken in a reverse order,i.e,A=26 ,B=25...,Z=1
G = 20 and O = 12 totaling 32
S = 8, H = 19 and E = 22 totaling 49

So
SOME = 8 + 12 + 14 + 22 = 56.

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Filed Under: Coding and Decoding
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE , TOEFL
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

102 26553
Q:

In the following question, select the missing number from the given series.

123, 120, 116, 111, ?, 98

 

A) 100 B) 105
C) 99 D) 103
 
Answer & Explanation Answer: B) 105

Explanation:
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Filed Under: Number Series
Exam Prep: Bank Exams

1 26538
Q:

Which of the following terms follows the trend of the given list?

 

abaBABAB, AbabABAB, ABabaBAB, ABAbabAB, ABABabaB, _______________.

 

A) aBABABab B) ABABAbab
C) abaBABAB D) AbabABAB
 
Answer & Explanation Answer: B) ABABAbab

Explanation:
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Filed Under: Alphabet Test
Exam Prep: Bank Exams

1 26525
Q:

In how many ways can 5 different toys be packed in 3 identical boxes such that no box is empty, if any of the boxes may hold all of the toys ?

A) 36 B) 25
C) 24 D) 72
 
Answer & Explanation Answer: B) 25

Explanation:

The toys are different; The boxes are identical 

 

If none of the boxes is to remain empty, then we can pack the toys in one of the following ways 

a. 2, 2, 1 

b. 3, 1, 1 

 

Case a. Number of ways of achieving the first option 2 - 2 - 1 

 

Two toys out of the 5 can be selected in 5C2 ways. Another 2 out of the remaining 3 can be selected in 3C2 ways and the last toy can be selected in 1C1 way. 

 

However, as the boxes are identical, the two different ways of selecting which box holds the first two toys and which one holds the second set of two toys will look the same. Hence, we need to divide the result by 2 

 

Therefore, total number of ways of achieving the 2 - 2 - 1 option is ways 5C2*3C2= 15 ways

 

 

Case b. Number of ways of achieving the second option 3 - 1 - 1

 

Three toys out of the 5 can be selected in 5C3 ways. As the boxes are identical, the remaining two toys can go into the two identical looking boxes in only one way.

 

Therefore, total number of ways of getting the 3 - 1 - 1 option is 5C3 = 10 = 10 ways.

 

 

 

Total ways in which the 5 toys can be packed in 3 identical boxes

 

= number of ways of achieving Case a + number of ways of achieving Case b= 15 + 10 = 25 ways.

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34 26523
Q:

Which of the following terms follows the trend of the given list?

 

XXXXXXx, XXXXXxX, XXXXxXX, XXXxXXX, XXxXXXX, _______________.

 

A) xXXXXXX B) XXXXXXx
C) XxXXXXX D) XXXXXxX
 
Answer & Explanation Answer: C) XxXXXXX

Explanation:
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Filed Under: Alphabet Test
Exam Prep: Bank Exams

1 26503
Q:

Is Arun taller than Sachin ? 

I. Dinesh is of the same height as Arun and Sachin. 

II. Sachin is not shorter than Dinesh. 

A) If the data in statement I alone are sufficient to answer the question B) If the data in statement II alone are sufficient answer the question
C) If the data either in I or II alone are sufficient to answer the question; D) If the data even in both the statements together are not sufficient to answer the question
 
Answer & Explanation Answer: A) If the data in statement I alone are sufficient to answer the question

Explanation:

From statement I, we can conclude that Dinesh. Arun and Sachin are of the same height So. Arun is not taller than Sachin. Thus, only statement I is sufficient to answer the question. .

 

 

 

 

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Filed Under: Data Sufficiency

16 26478