Aptitude and Reasoning Questions

Q:

A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. What is the total distance traveled by the man ?

A) 4.58 kms B) 6.35 kms
C) 5.76 kms D) 5.24 kms
 
Answer & Explanation Answer: C) 5.76 kms

Explanation:

Speed in still water = 6 kmph

Stream speed = 1.2 kmph

Down stream  = 7.2 kmph

Up Stream = 4.8 kmph

x/7.2 + x/4.8 = 1

x = 2.88

Total Distance  = 2.88 x 2 = 5.76 kms

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

37 26474
Q:

Find the area of a right-angled triangle whose base is 12 cm and hypotenuse is 13cm.

A) 30 B) 40
C) 50 D) 60
 
Answer & Explanation Answer: A) 30

Explanation:

Height of the triangle = 132-122=25 = 5 cm.

 

Its area =12*base*height12*12*530cm2.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

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Q:

Two numbers are in the ratio of 15 : 11.If their HCF is 13. Find  the numbers.

 

A) 195, 143 B) 196, 143
C) 195, 141 D) 195, 142
 
Answer & Explanation Answer: A) 195, 143

Explanation:
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Filed Under: HCF and LCM
Exam Prep: Bank Exams

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Q:

If Deepesh had walked 20 km/h faster he woulh have saved 1 hour in the distance of 60km. what is the usual speed of Deepesh?

A) 100 B) 120
C) 150 D) None of these
 
Answer & Explanation Answer: A) 100

Explanation:

Let the original speed  be x km/h, then

600x-600x+20=1 

 

600x+20-xxx+20=1  

 

x2+120x-12000=0

 

x-120x-100=0

 

Therefore,  original speed = 100km/h

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Filed Under: Time and Distance

32 26427
Q:

What will be the total weight of 10 poles each of the same weight ?

I. One-fourth of the weight of a pole is 5 kilograms.

II. The total weight of three poles is 20 kilograms more than the total weight of two poles. 

A) If the data in statement I alone are sufficient to answer the question B) If the data in statement II alone are sufficient answer the question
C) If the data either in I or II alone are sufficient to answer the question; D) If the data even in both the statements together are not sufficient to answer the question
 
Answer & Explanation Answer: C) If the data either in I or II alone are sufficient to answer the question;

Explanation:

From I, we find that the weight of one pole is (5 x 4) = 20 kg ,and so the weight of 10 poles is 200 kg.

Thus, I alone is sufficient.

From II. we have : (weight of 3 poles — weight of 2 poles) -= 20 kg or weight of one pole - 20 kg.

So. weight of 10 poles 200 kg.

Thus. II alone is also sufficient 

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Filed Under: Data Sufficiency

24 26376
Q:

In a mixture of milk and water, there is only 26% water. After replacing the mixture with 7 liters of pure milk , the percentage of milk in the mixture  become 76%. The quantity of mixture is:

A) 65 liters B) 91 liters
C) 38 liters D) None of these
 
Answer & Explanation Answer: B) 91 liters

Explanation:

         Milk             Water 

         74%             26%        (initially) 

         76%             24%        ( after replacement) 

 

  Left amount = Initial amount 1-replaced amounttotal amount 

   24  = 261-7k

=> k = 91 

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Filed Under: Alligation or Mixture

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Q:

Which one of the following Venn diagrams best illustrates the three classes.

Rhombus, Quadrilaterals, Polygons

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: A) 1

Explanation:
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Filed Under: Logical Venn Diagram
Exam Prep: Bank Exams

7 26343
Q:

If the letters of the word CHASM are rearranged to form 5 letter words such that none of the word repeat and the results arranged in ascending order as in a dictionary what is the rank of the word CHASM ?

A) 32 B) 24
C) 72 D) 36
 
Answer & Explanation Answer: A) 32

Explanation:

The 5 letter word can be rearranged in 5!=120 Ways without any of the letters repeating.

The first 24 of these words will start with A.

Then the 25th word will start will CA _ _ _.
The remaining 3 letters can be rearranged in 3!=6 Ways. i.e. 6 words exist that start with CA.

The next word starts with CH and then A, i.e., CHA _ _.
The first of the words will be CHAMS. The next word will be CHASM.

Therefore, the rank of CHASM will be 24+6+2= 32

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