# Aptitude and Reasoning Questions

A) 20% | B) 21% |

C) 22% | D) 23% |

Explanation:

Gain % = $\left(\frac{{\left(100+commongain\%\right)}^{2}}{100}-100\right)$%

=$\left(\frac{{\left(100+10\right)}^{2}}{100}-100\right)$

= 21%

A) 2/91 | B) 1/22 |

C) 3/22 | D) 2/77 |

Explanation:

Let S be the sample space.

Then, n(S) = number of ways of drawing 3 balls out of 15 = $15{C}_{3}$ =$\frac{15*14*13}{3*2*1}$= 455.

Let E = event of getting all the 3 red balls.

n(E) = $5{C}_{3}$ = $\frac{5*4}{2*1}$ = 10.

=> P(E) = n(E)/n(S) = 10/455 = 2/91.

A) 2/7 | B) 5/7 |

C) 1/5 | D) 1/2 |

Explanation:

Total number of outcomes possible, n(S) = 10 + 25 = 35

Total number of prizes, n(E) = 10

$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{10}{35}=\frac{2}{7}$

A) 14 | B) 19 |

C) 33 | D) 38 |

Explanation:

Let the son's present age be x years .Then, (38 - x) = x => x= 19.

Son's age 5 years back = (19 - 5) = 14 years

A) 10000 | B) 12000 |

C) 14000 | D) 16000 |

Explanation:

Purchase price = $Rs.\left[\frac{8748}{{{}^{\left(1-{\displaystyle \frac{10}{100}}\right)}}^{3}}\right]$ = Rs. [8748 * (10/9) * (10/9 )* (10/9)] = Rs.12000

A) Monday | B) Wednesday |

C) Tuesday | D) Friday |

A) 20 | B) 30 |

C) 40 | D) 50 |

Explanation:

The fruit content in both the fresh fruit and dry fruit is the same.

Given, fresh fruit has 68% water.so remaining 32% is fruit content. weight of fresh fruits is 100kg

Dry fruit has 20% water.so remaining 80% is fruit content.let weight if dry fruit be y kg.

Fruit % in freshfruit = Fruit% in dryfruit

Therefore, (32/100) x 100 = (80/100 ) x y

we get, y = 40 kg.

A) 48 | B) 50 |

C) 58 | D) 60 |

Explanation:

Take a Look at this series :

${2}^{3}$ - ${2}^{2}$ = 8 - 4 = 4

${3}^{3}$ - ${3}^{2}$ = 27 - 9 = 18

${4}^{3}$ - ${4}^{2}$ = 64 - 16 = 48

${5}^{3}$ - ${5}^{2}$ = 125 - 25 = 100

${6}^{3}$ - ${6}^{2}$ = 216 - 36 = 180

${7}^{3}$ - ${7}^{2}$ = 343 - 49 = 294

${8}^{3}$ - ${8}^{2}$ = 512 - 64 = 448