# Aptitude and Reasoning Questions

• #### Verbal Reasoning - Mental Ability

Q:

Two cards are drawn at random from a pack of 52 cards.what is the probability that either both are black or both are queen?

 A) 52/221 B) 55/190 C) 55/221 D) 19/221

Explanation:

We have n(s) =$52C2$ 52 = 52*51/2*1= 1326.

Let A = event of getting both black cards

B = event of getting both queens

A∩B = event of getting queen of black cards

n(A) = $52*512*1$ = $26C2$ = 325, n(B)= $26*252*1$= 4*3/2*1= 6  and  n(A∩B) = $4C2$ = 1

P(A) = n(A)/n(S) = 325/1326;

P(B) = n(B)/n(S) = 6/1326 and

P(A∩B) = n(A∩B)/n(S) = 1/1326

P(A∪B) = P(A) + P(B) - P(A∩B) = (325+6-1) / 1326 = 330/1326 = 55/221

339 119314
Q:

A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:

 A) 2/91 B) 1/22 C) 3/22 D) 2/77

Explanation:

Let S be the sample space.

Then, n(S) = number of ways of drawing 3 balls out of 15 = $15C3$  =$15*14*133*2*1$= 455.

Let E = event of getting all the 3 red balls.

n(E) = $5C3$ = $5*42*1$ = 10.

=> P(E) = n(E)/n(S) = 10/455 = 2/91.

189 115685
Q:

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

 A) Monday B) Friday C) Sunday D) Tuesday

Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday

628 113379
Q:

Find the missing number in the following series?

3, 5, 5, 19, 7, 41, 9, ?

 A) 71 B) 61 C) 79 D) 69

Explanation:

Fiest series : 3, 5, 7, 9

Second series : 5, 19, 41, ?

Difference of Second series are 14, 22, 30 etc

Next term is 41+30 i.e equal to 71

1035 112900
Q:

A shopkeeper cheats to the extent of 10% while buying and selling, by using false weights. His total gain is.

 A) 20% B) 21% C) 22% D) 23%

Explanation:

Gain % = %

=$100+102100-100$

= 21%

614 112167
Q:

In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?

 A) 2/7 B) 5/7 C) 1/5 D) 1/2

Explanation:

Total number of outcomes possible, n(S) = 10 + 25 = 35

Total number of prizes, n(E) = 10

$P(E)=n(E)n(S)=1035=27$

253 112004
Q:

How many 4's are there preceded by 7 but not followed by 3?

5  9  3  2  1  7  4  2  6  9  7  4  6  1  3  2  8  7  4  1  3  8  3  2  5  6  7  4  3  9  5  8  2  0  1  8  7  4  6  3

 A) Four B) Three C) Six D) Five

Explanation:

7  4  2

7  4  6

7  4  1

7  4  6

Only at these placees 4 is preceded by 7 but not followed by 3

976 110535
Q:

Find the odd man out.

6, 9, 15, 21, 24, 28, 30

 A) 28 B) 21 C) 24 D) 30