# Aptitude and Reasoning Questions

A) 50 kmph | B) 60 kmph |

C) 70 kmph | D) 80 kmph |

Explanation:

Speed of tractor = 360/12 = 30 kmph

Speed of jeep = 250 x 30/100 = 75 kmph

But, given ratio of speed of car, jeep and tractor is 3 : 5 : 2

Speed of car = 3 x 75/5 = 45 kmph

Required, average speed of car and jeep = **75 + 45/2** = **60 kmph**.

A) 2 | B) 0 |

C) 1 | D) 50 |

Explanation:

50.003% of 99.8 **÷ **49.988 = ?

? ~= (50 x 100/100)/50

? ~= (50 x 100)/(100 x 50)

**? ~= 1**

A) 27 | B) 38 |

C) 55 | D) 75 |

Explanation:

The given series is 15, 19, 27, 38, 55, 75

15

15 + 4 = 19

19 + 8 = 27

27 + 12 = 39

39 + 16 = 55

55 + 20 = 75

Hence, the odd number in the given series is 38.

A) 0.25 | B) 0.45 |

C) 0.60 | D) 0.75 |

Explanation:

Given fraction is 3/5

Now, multiply with 2 for numerator and denominator

we get,

3/5 x 2/2 = 6/10

When we divide, 6 with 10, we get 0.6 as quotient.

Hence, **3/5 as a decimal fraction is 0.6.**

A) An exact match is not possible in a SELECT statement. | B) An exact match is necessary in a CREATE statement. |

C) An exact match is not possible in a CREATE statement. | D) An exact match is necessary in a SELECT statement. |

A) 978 | B) 1024 |

C) 988 | D) 1012 |

Explanation:

The given series is 1000, 1012, 988, 1024, 978

1000

1000 + 12 = 1012

1012 - 24 = 988

988 + 36 = 1024

1024 - 48 = 976 (**Not 978**)

A) Rs. 600 | B) Rs. 768 |

C) Rs. 878 | D) Rs. 668 |

Explanation:

We know that,

P.W = 100×T.D/R×T

= 100×168/14×2

P.W = 600.

Now, required Sum = (P.W. + T.D.)

= Rs. (600 + 168)

= Rs. 768.

A) 1/6 | B) 2/3 |

C) 14/33 | D) 5/6 |

Explanation:

Possible outcomes = (RY, YP, PR)

2C1 4C1 + 4C1 6C1 + 6C1 2C1

Required probability = (2C1 4C1 + 4C1 6C1 + 6C1 2C1)/(12C2)

= 8 + 24 + 12/66

= 44/66

= 2/3.