Aptitude and Reasoning Questions

Q:

A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ?

A) 1:3 B) 2:1
C) 3:2 D) 2:3
 
Answer & Explanation Answer: C) 3:2

Explanation:

Let us assume S as number of shirts and T as number of trousers
Given that each trouser cost = Rs.70 and that of shirt = Rs.30
Therefore, 70 T + 30 S = 810
=> 7T + 3S = 81......(1)
T = ( 81 - 3S )/7

We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of T
Simplifying by taking 3 as common factor i.e, 3(27-S) / 7
In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7

Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9

Hence for S, put T in eq(1), we get
S = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.
The ratio of T:S = 9:6 = 3:2.

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Filed Under: Ratios and Proportions
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14 8910
Q:

What should come next in the following letter series based on English alphabet ?
CEA JLH QSO ?

A) WYU B) UXW
C) WXV D) XZV
 
Answer & Explanation Answer: D) XZV

Explanation:

In the given series, each letter moves seven letters forward to obtain the next.
So, XZV replaces ? in the series.

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Filed Under: Alphabet Test
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13 8909
Q:

How many meshes are there in 1 squrare meter of wire gauge if each mesh is 8mm long and 5mm wide ?

A) 2500 B) 25000
C) 12500 D) 15400
 
Answer & Explanation Answer: B) 25000

Explanation:

We know that,

 

One square meter is equal to 10,00,000 sq mm.
Given, each mesh is 8mm length and 5mm wide
Therefore for each mesh : 8 x 5 = 40 sq mm.
So, number of meshes = 100000040 = 25000.

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Filed Under: Volume and Surface Area
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
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6 8906
Q:

Water boils at 212°F or 100°C and melts at 32°F or 0°C .  If the temparature of the particular day  is 35°C , it is equal  to :

A) 85°F B) 95°F
C) 96°F D) 97°F
 
Answer & Explanation Answer: B) 95°F

Explanation:

Let F and C denotes the temparature in Fahrenheit anid Celcsius respectively.

Then, (F - 32) /(212 - 32) = (C - 0)/(100 - 0),  if c = 35, then F = 95.

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Filed Under: Simplification

6 8903
Q:

k, l, m together started a business. k invested Rs.6000 for 5 months l invested Rs.3600 for 6 months and m Rs.7500 for 3 months. If they get a total profit of Rs.7410. Find the share of l ?

A) Rs. 1640 B) Rs. 2500
C) Rs. 2160 D) Rs. 3000
 
Answer & Explanation Answer: C) Rs. 2160

Explanation:

=> 60x5 : 36x6 : 75x3

=> 100 : 72 : 75

=> 72/247 x 7410 = Rs. 2160

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Filed Under: Partnership
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5 8902
Q:

The perimeter of a rectangle is 160 cm. The rectangle is 4 times longer than wide. What are the length and width of this rectangle?

A) l=65;b=16 B) l=16;b=64
C) l=64;b=16 D) l=16;b=48
 
Answer & Explanation Answer: C) l=64;b=16

Explanation:

P=2(l+b)

l=4b

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

9 8902
Q:

Legend : Story : : Merlin : ?

A) Eagle B) Parakeet
C) Hawk D) crow
 
Answer & Explanation Answer: C) Hawk

Explanation:

First is a type of second.

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Filed Under: Analogy

8 8897
Q:

Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30º and 45º respectively. If the lighthouse is 100 m high, the distance between the two ships is:

A) 173 m B) 200 m
C) 273 m D) 300 m
 
Answer & Explanation Answer: C) 273 m

Explanation:

 Let AB be the lighthouse and C and D be the positions of the ships.

 

 

Then, AB = 100m, ACB = 30°andADB =45°

 

ABAC=tan30°=13=>AC=AB*3=1003m

 

 

 ABAD=tan45°=1=>AD=AB=100m

CD=(AC+AD)=1003+100m=1003+1=100*2.73=273m

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Filed Under: Height and Distance

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