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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

If logx916 = -12, then the value of x?

A) -3/4 B) 3/4
C) 81/256 D) 256/81
 
Answer & Explanation Answer: D) 256/81

Explanation:
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Filed Under: Logarithms
Exam Prep: Bank Exams
Job Role: Bank PO

88 8824
Q:

14 persons are seated around a circular table. Find the probability that 3 particular persons always seated together.

A) 11/379 B) 21/628
C) 24/625 D) 26/247
 
Answer & Explanation Answer: C) 24/625

Explanation:

Total no of ways = (14 – 1)! = 13!

Number of favorable ways = (12 – 1)! = 11!

 

So, required probability = 11!×3!13! = 39916800×66227020800 = 24625

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Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

22 8823
Q:

P, Q, R, S, T and U are six consecutive odd numbers and their average is 52. What is the product of P and U ?

A) 2212 B) 2154
C) 2349 D) 2679
 
Answer & Explanation Answer: D) 2679

Explanation:

Let x, x+2, x+4, x+6, x+8 and x+10 are six consecutive odd numbers.

Given that their average is 52

Then, x + x+2 + x+4 + x+6 + x+8 + x+10 = 52×6

6x + 30 = 312

x = 47

So Product = 47 × 57 = 2679

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Filed Under: Average
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

22 8820
Q:

How many A's are there in the following sequence which are immediately followed by B as well as immediately preceded by Z?

 

A M B Z A N A A B Z A B A Z B A P Z A B A Z A B 

A) Three B) Two
C) One D) More than three
 
Answer & Explanation Answer: A) Three

Explanation:

The letter A satisfying the following Structure ZAB

 

A M B Z A N A A B Z A B A Z B A P Z  A B A Z A B 

 

Answer (A) is correct

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Filed Under: Alphabet Test
Exam Prep: AIEEE , Bank Exams , CAT

5 8819
Q:

In a mens hostel, there were 95 students. To accommodate 30 more students the average is decreased by rupees 5. But total expenditure increased by Rs.500. Find the total expenditure of the hostel now ?

A) Rs. 4680 B) Rs. 4420
C) Rs. 4960 D) Rs. 5480
 
Answer & Explanation Answer: A) Rs. 4680

Explanation:

Let the expenditure on the 95 students be 'x'

Then,

95x + 500 = 120(x – 5)
95x + 500 = 120x - 600
120x - 95x = 1100
25x = 1100
=> x = 44

Therefore, total expenditure of the hostel becomes
95 x 44 + 500 = 4680.

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Filed Under: Average
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

18 8811
Q:

If the letters of the word VERMA are arranged in all possible ways and these words are written out as in a dictionary, then the rank of the word VERMA is :

A) 108 B) 117
C) 810 D) 180
 
Answer & Explanation Answer: A) 108

Explanation:

The number of words beign with A is 4! 

The number of words beign with E is 4! 

The number of words beign with M is 4! 

The number of words beign with R is 4!

 

Number of words beign with VA is 3! 

Words beign with VE are VEAMR 

VEARM

VEMAR

VEMRA

VERAM

VERMA 

Therefore, The Rank of the word VERMA = 4 x 4! + 3! + 6 = 96 + 6 + 6 =108             

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Filed Under: Permutations and Combinations
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

4 8809
Q:

Which is the third number to the left of the number which is exactly in the middle of the following sequence of numbers?

1  2  3  4  5  6  7  8  9  2  4  6  8  9  7  5  3  1  9  8  7  6  5  4  3  2  1

A) 3 B) 5
C) 4 D) 7
 
Answer & Explanation Answer: C) 4

Explanation:

There are 27 numbers in the given sequence 

So, middle number = 14th number = 9

Clearly, the third number to the left of this 9 is 4

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Filed Under: Number, Ranking and Time Sequence Test

18 8809
Q:

Choose the correct alternative that will continue the same pattern and replace 'x' in given series 1,2,6,15,31,56,x

A) 65 B) 78
C) 81 D) 92
 
Answer & Explanation Answer: D) 92

Explanation:

The pattern is + 1*1,+ 2*2, +3*3, + 4*4,+ 5*5,+ 6*6, . . . . . . .
So missing term is 56+36=92

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Filed Under: Number Series

12 8794