Sawaal
  • Home/
  • Aptitude and Reasoning

Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

The arithmetic mean of the following numbers 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6 and 7, 7, 7, 7, 7, 7, 7 is   ?

A) 6 B) 9
C) 7 D) 5
 
Answer & Explanation Answer: D) 5

Explanation:

Arithmatic mean = sum/members 

=> (1x1 + 2x2 + 3x3 + 4x4 + 5x5 + 6x6 + 7x7) / (1 + 2 + 3 + 4 + 5 + 6 + 7)

=> 140/28 = 5

Report Error

View Answer Report Error Discuss

Filed Under: Arithmetical Reasoning
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

4 7416
Q:

Course materials are sent to students by a distance teaching institution. The probability that they will send a wrong programme’s study material is 1/5. There is a probability of 3/4 that the package is damaged in transit, and there is a probability of 1/3 that there is a short shipment. What is the probability that the complete material for the course arrives without any damage in transit? 

A) 4/5 B) 2/3
C) 1/2 D) 2/15
 
Answer & Explanation Answer: D) 2/15

Explanation:

Probability of sending the correct material is 4/5

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Probability of the material not being damaged in transit is 1/4

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Probability that there is no short shipment = 2/3

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

∴ Required probability =4/5 x 1/4 x 2/3 = 2/15

Report Error

View Answer Report Error Discuss

Filed Under: Quantitative Aptitude - Arithmetic Ability

2 7412
Q:

In how many ways the letters of the word OLIVER be arranged so that the vowels in the word always occur in the dictionary order as we move from left to right ?

A) 186 B) 144
C) 136 D) 120
 
Answer & Explanation Answer: D) 120

Explanation:

In given word OLIVER there are 3 vowels E, I & O. These can be arranged in only one way as dictionary order E, I & O.

 

There are 6 letters in thegiven word.

 

First arrange 3 vowels.

 

This can be done in 6C3 ways and that too in only one way.(dictionary order E, I & O)

 

Remaining 3 letters can be placed in 3 places = 3! ways

 

Total number of possible ways of arranging letters of OLIVER = 3! x C36 ways = 6x5x4 = 120 ways.

Report Error

View Answer Report Error Discuss

Filed Under: Permutations and Combinations
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

11 7411
Q:

How many ways are there to deal a five-card hand consisting of three eight's and two sevens?

A) 36 B) 72
C) 24 D) 16
 
Answer & Explanation Answer: C) 24

Explanation:

If a card hand that consists of four Queens and an Ace is rearranged, nothing has changed.

 

The hand still contains four Queens and an Ace. Thus, use the combination formula for problems with cards.

 

We have 4 eights and 4 sevens.

We want 3 eights and 2 sevens.

C(have 4 eights, want 3 eights) x C(have 4 sevens, want 2 sevens) 

C(4,3) x C(4,2) = 24

 

Therefore there are 24 different ways in which to deal the desired hand.

Report Error

View Answer Report Error Discuss

Filed Under: Permutations and Combinations

1 7408
Q:

Only if Sheela is happy, then she does not go to work.

A) Sheela is not happy and she goes to work. B) Sheela is happy and she does not go to work
C) Sheela is not happy and she does not go to work. D) Sheela is happy and she goes to work.
 
Answer & Explanation Answer: A) Sheela is not happy and she goes to work.

Explanation:

The event of "Sheela is not going to work" happens only when the event "Sheela is happy" happens. Also, if the event "Sheela is happy" does not happen, then the event "Sheela is not going to work" will not happen. In other words, if it is true that Sheela is not happy, then it means that Sheela is going to work.

Report Error

View Answer Report Error Discuss

Filed Under: Verification of Truth of the statement
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration

21 7397
Q:

If 18225=135, then the value of 182.25 +1.8225+0.018225+0.00018225  is:

A) 1.49985 B) 14.9985
C) 149.985 D) 1499.85
 
Answer & Explanation Answer: B) 14.9985

Explanation:

Given exp = 18225102+18225104+18225106+18225108

 

               = 1822510+18225102+18225103+18225104

 

               = 13510+135100+1351000+13510000

 

               = 13.5+1.35+0.135+0.0135=14.9985

Report Error

View Answer Report Error Discuss

Filed Under: Square Roots and Cube Roots

25 7391
Q:

In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:

A) 21 m B) 26 m
C) 28m D) 29m
 
Answer & Explanation Answer: C) 28m

Explanation:

A : B = 100 : 75

 

B : C = 100 : 96.

 

A : C = (A/B*B/C) = (100/75*100/96) = 100/72  =100:72     

 

   A beats C by (100 - 72) m = 28 m.

Report Error

View Answer Report Error Discuss

Filed Under: Races and Games

24 7390
Q:

What do you understand by - 'If K is there L has to be there'

A) K & L will always be together B) K is not there, then L will not be there
C) k is there, then L will also be there D) K & L will always be not together
 
Answer & Explanation Answer: C) k is there, then L will also be there

Explanation:

This would not mean that K and L will always be together. It just implies that, if K is there, then L will also be there.

At the same time, it can happen that L is there but K isn't.

Remember, the condition is on K, not on L.

Report Error

View Answer Report Error Discuss

Filed Under: Analytical Reasoning
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE , TOEFL
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

17 7388