Aptitude and Reasoning Questions

Let 'A' be the cost price of property P1.

Then from the given data, the selling price of P1 = Rs. 1,00,000

He got 20% loss on selling P1

$$\begin{gathered} ⇒A - 20A100 = 100000 \\ ⇒A = 1,25,000 \end{gathered}$$

Therefore, the amount he lossed on selling P1 = 25,000

As ge he got no loss or gain on sale of P1 and P2, the gain on selling P2 = 25,000

But the selling price of P2 = 1,00,000 => Cost price of P2 = 75,000

Hence, the profit percentage on P2 = GainCPx 100 = 2500075000x100 = 1003= 33.33%

The given series follow the rule that :

Multiplying consecutive prime numbers
2,3,5,7,11,13,17,19....
2x3 = 6
3x5 = 15
5x7 = 35
7x11 = 77
11x13 = 143
13x17 = 221
So, the wrong term is 165.

Given Number :  7 6 5 3 4 2 1 8 

New Number :    8 7  6 4 5 3 2 9

Ascending Order :  2 3 4 5 6 7 8 9 

Fifth digit in the above ascending order arrangement is '6' . Hence option(1) is the correct answer.

Here I am very happy to start this Program is correct statement.

"Too" is not used with pleasant adjectives. It means 'more than required' and is usually used with unpleasant adjectives.

So, 'too healthy', 'too happy', 'too glad' etc are wrong.

S = { 1, 2, 3, 4, .....18 } 

=> n(S) = 18

E1 = {2, 4, 6, 8, 10, 12, 14, 16, 18}

=> n(E1) = 9

E2 = {3, 6, 9, 12, 15, 18 }

=> n(E2) = 6

 E3 =E1∩E2={6, 12, 18} 

=> n(E3) = 3

∴E=E1 ∪ E2 = E1+E2-E3 

=> n(E) = 9 + 6 - 3 =12

 where E = { 2, 3, 4, 6, 8, 9, 10, 12, 12, 14, 15, 16, 18 }

∴P(E)=n(E)n(S)=1218=23

The first, fourth, seventh and eleventh letters of the word 'SUPERFLUOUS' 

The word formed is LESS

Therefore, The first letter is L.

The number of exhaustive events = 100 C₁ = 100.

We have 25 primes from 1 to 100.

Number of favourable cases are 75.

Required probability = 75/50 = 3/2.

25 Jan, 1981 = (1980 years + Period from 1.1.1981 to 25.1.1981)

Odd days in 1600 years = 0

Odd days in 300 years = 1

80 years = (60 ordinary years + 20 leap year) = (60 x 1 + 20 x 2)= 2 odd days

Jan = 25 days = (3 weeks + 4 days) = 4 odd days.

Total number of odd days = (0 + 1 + 2 + 4) = 7= 0 odd day.

Given day is Sunday.