What are Different sections in Aptitude and Reasoning Question and Answers?
In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are:
Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).
Why Aptitude and Reasoning Questions?
Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.
What type of questions are there in Aptitude and Reasoning tests?
Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.
Marked price of an article is 1600 Rs. more than the cost price. When the same article is sold at a discount of Rs. 500 then the percent profit earned is 25%. For earning a profit of 30%, the article should be sold at what price?
The average temperature of Monday to Wednesday was 37 C and of Tuesday to Thursday was 34 C. If the temperature on Thursday was 4/5 th of that of Monday, the temperature on Thursday was ?
Δ DEF and Δ GHI are similar triangles. Length of AB is 10 cm and length of the corresponding side DE is 6 cm. What is the ratio of Perimeter of ΔABC to ΔDEF?
we can treat every two consecutive terms as one. So, we will have a total of 100 terms of the nature: (2 + 5) + (7 + 6) + (12 + 7).... => 7, 13, 19,....
We know the sum of n terms
Now, a= 7, d=6 and n=100 Hence the sum of the given series is S= 100/2 x[2 x 7 + 99 x 6] => 50[608] => 30,400.
There are five bags. In the first bag we put some fruits. Each bag the number of fruits is reduced by 1/4. The last bag contains 4. Then the number of fruits in the first bag is ?
Fruits reduced by 1/4. Total no. of bags N = 5 Formula to find no. of fruits in 1st bag = 4^n Last Bag = 4 fruits. That means, 4th bag = 4 x 4 = 16 fruits 3rd bag = 16 x 4 = 64 fruits 2nd bag = 64 x 4 = 256 fruits 1st bag = 256 x 4= 1024 fruits.