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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

In the following question, various terms of an alphabet series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives. A, B, N, C, D, O, E, F, P, ?, ?, ?

A) G, H, Q B) J, K, L
C) G, H, J D) G, H, I
 
Answer & Explanation Answer: A) G, H, Q

Explanation:

The series consists of 2 groups (A, B, C, D, E, F, ?, ?) and (N, O, P, ?). The series is made of two terms of first group followed by one term of second group.

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Filed Under: Number Series

4 4946
Q:

What is the probability of getting a sum 9 from two throws of a dice ?

A) 1/6 B) 1/2
C) 1/9 D) 3/4
 
Answer & Explanation Answer: C) 1/9

Explanation:

In two throws of a die, n(s)=(6 x 6)=36

 

let E= Event of geting a sum 9={(3,6),(4,5),(5,4),(6,3)}

 

P(E) = n(E)/n(S) = 4/36 = 1/9

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Filed Under: Probability

3 4941
Q:

In a certain code language, "LOYALTY" is written as "MPZBMUZ". How is "PROCLAIM" written in that code language?

A) QSPDDBJN B) QSPDBMJN
C) QSPDMBJN D) QPSDMBJN
 
Answer & Explanation Answer: C) QSPDMBJN

Explanation:
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Filed Under: Coding and Decoding
Exam Prep: Bank Exams

3 4940
Q:

Find the odd man out 1 4 9 16 22 36?

A) 9 B) 16
C) 22 D) 36
 
Answer & Explanation Answer: C) 22

Explanation:

In the given series 1 4 9 16 22 36

1 = 1 x 1 

4 = 2 x 2

9 = 3 x 3

16 = 4 x 4

25 = 5 x 5 (Not 22)

36 = 6 x 6

 

Hence, the odd man in the series is 22.

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

13 4935
Q:

Jatin,Kamal and Navin are the 3 mountaineers.Jatin is kamals brother.Kamal is navinsbrother .Navin is not Jatin's brother.Therefore,Navin is jatin's brother

A) True B) Probably false
C) False D) Can't say
 
Answer & Explanation Answer: A) True

Explanation:
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Filed Under: Blood Relations

2 4934
Q:

Count the number of cubes in the given figure.

A) 45 B) 46
C) 48 D) 49
 
Answer & Explanation Answer: B) 46

Explanation:

In the figure, there are 21 columns containing 2 cubes each and 4 columns containing 1 cube each. 

∴Total number of cubes = (21 x 2) + (4 x 1) = 42 + 4 = 46.

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Filed Under: Cubes and Dice
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

19 4931
Q:

Two boxes contain 4 and 16 balls respectively. Two balls in the first box and four in the second, are black. If a box is chosen randomly and two balls are drawn at random from it, what is the
probability that at least one ball is black if the ball is not replaced?

A) 11/20 B) 43/120
C) 77/120 D) 9/20
 
Answer & Explanation Answer: C) 77/120

Explanation:

At least one black can be chosen in two ways from each box:
Now, probability of choosing at least one black ball from first box 

= 1/2 × [ (2C1× 2C1)/4C2 + 2C2/ 4C2 ]= 5/12

Probability of choosing at least one black ball from 2nd box
= 1/2 × [(4C1×12C1)/16C2 + 4C2/ 16C2] = 9/40

Final probability

= 5/12 + 9/40 = (50 + 27)/120 = 77/120

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

5 4930
Q:

Which number replaces 'x' in the below figure ?

k11483336561.jpg image

A) 2 B) 9
C) 11 D) 12
 
Answer & Explanation Answer: B) 9

Explanation:

k11483336735.jpg image

 

Here in 2nd column if you add the individual digits

 we get  3 + 7 + 0 =10 , 2 + 2 + 4 = 8 , 7 + 3 + 0 = 10

 

7   10   3  --> 7+3 =10

 

6   8     2  --> 6+2 =8

 

x   10   1  --> x+1 =10

 

Here we can observe that by adding 1st and 3rd column elements we get 2nd column elements

 --> x = 9

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Filed Under: Inserting The Missing Character
Exam Prep: GRE , GATE , CAT , Bank Exams
Job Role: Bank PO , Bank Clerk

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