Aptitude and Reasoning Questions

Q:

On dividing a number by 96, we get 271 as quotient and 0 as remainder. On dividing the same number by 95, what will be the remainder ?

A) 87 B) 59
C) 92 D) 81
 
Answer & Explanation Answer: D) 81

Explanation:

Number = 271 x 96 + 0 = 26016

=> 95) 26016 (273
           25935
           --------
              81

Required number = 81.

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Filed Under: Problems on Numbers
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4 4920
Q:

In the following question, select the missing number from the given series.
13, 27, 56, 115, ?

A) 224 B) 231
C) 233 D) 234
 
Answer & Explanation Answer: D) 234

Explanation:
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Filed Under: Number Series
Exam Prep: Bank Exams

10 4918
Q:

The true-discount on Rs.2480 due after a certain period at 5% is Rs.80. Find the due period.

A) 6months B) 5months
C) 8months D) 3months
 
Answer & Explanation Answer: C) 8months

Explanation:

P.W= Amount – (T.D)

 

Time = 100×TDPW×R

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Filed Under: True Discount
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6 4918
Q:

Find the next number in the series 64, 2, 32, 72, 3, 24, 76, 4, 19, ....., 5, 15.6

A) 80 B) 78
C) 72 D) 70
 
Answer & Explanation Answer: B) 78

Explanation:

The pattern is 2x32=64, 3x24=72, 4x19=76

The next number = 5x15.6=78

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Filed Under: Number Series
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10 4916
Q:

A is brother of B, C is daughter of B, D is husband of B, E is daughter of A, What is the relationship between C and D ?

A) Mother & Son B) Father & Daughter
C) Mother & Daughter D) Father & Son
 
Answer & Explanation Answer: B) Father & Daughter

Explanation:
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Filed Under: Blood Relations
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30 4914
Q:

Let K and L be events on the same sample space, with P (K) = 0.8 and P (B) = 0.6. Are these two events are disjoint ?

A) TRUE B) FALSE
Answer & Explanation Answer: B) FALSE

Explanation:

These two events cannot be disjoint because P(K) + P(L) > 1.


P(AꓴB) = P(A) + P(B) - P(AꓵB).


An event is disjoint if P(A ꓵ B) = 0. If K and L are disjoint P(K ꓴ L) = 0.8 + 0.6 = 1.4


And Since probability cannot be greater than 1, these two mentioned events cannot be disjoint.

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Subject: Probability
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3 4914
Q:

The value of log2log5625 is :

A) 2 B) 5
C) 10 D) 15
 
Answer & Explanation Answer: A) 2

Explanation:
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Filed Under: Logarithms
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16 4913
Q:

Eight first class and six second class petty officers are on the board of the 56 club. In how many ways can the members elect, from the board, a president, a vice-president, a secretary, and a treasurer if the president and secretary must be first class petty officers and the vice-president and treasurer must be second class petty officers?

A) 1500 B) 1860
C) 1680 D) 1640
 
Answer & Explanation Answer: C) 1680

Explanation:

Since two of the eight first class petty officers are to fill two different offices, we write 8P2=56

 

Then, two of the six second class petty officers are to fill two different offices; thus, we write 6P2 =30

 

The principle of choice holds in this case; therefore, the members have 56 x 30 = 1680 ways to select the required office holders

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0 4912