Q:
      
      
         
            
The diluted wine contains only 8 liters of wine and the rest is water. A new mixture whose concentration is 30%, is to be  formed by replacing wine. How many liters of mixture shall be replaced with pure wine if there was initially 32 liters of water in the mixture ?
         
       
      
      
      
          
      
      
          Answer & Explanation
         Answer: B) 5         
         
Explanation:            Wine                         Water
            8L                              32L
            1                :               4
           20 %                           80% (original ratio)
           30 %                           70% (required ratio)
 
In  ths case, the percentage of water being reduced when the mixture is being replaced with wine.
 
so the ratio of left quantity to the initial quantity is 7:8
 
Therefore , 
 
=> K = 5 Lit
       
      
      
      
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