# Aptitude and Reasoning Questions

A) 20 | B) 12 |

C) 8 | D) 4 |

Explanation:

Let the required number be 'p'.

From the given data,

p + 12 = 160 x 1/p

=> p + 12 = 160/p

=> p(p + 12) = 160

=> P^2 + 12p - 160 = 0

=> p^2 + 20p - 8p - 160 = 0

=> P(p + 20) - 8(p + 20) = 0

=> (p + 20)(p - 8) = 0

=> p = -20 or p = 8

As, given the number is a natural number, so it can't be negative.

Hence, the required number **p = 8.**

A) 37804 | B) 2015736 |

C) 36718 | D) 53810 |

Explanation:

Divisibility rule for 24 is the number should be divisible by 3 and 8. As we know that 24 = 3 x 8

Now,

**Divisibility rule for 3 :**

If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.

**Divisibility rule for 8 :**

The last three digits of a number should be divisible by 8.

Hence, check for the given options,

A) 37804 => 804 is not divible by 8.

C) 36718 => 718 is not divible by 8.

D) 53810 => 810 is not divible by 8.

B) 2015736 => 736 is divisble by 8 and sum 2 + 0 + 1 + 5 + 7 + 3 + 6 = 24 which is divisible by 3.

Hence, **2015736 is divisible by 24.**

A) even | B) odd |

C) 0 | D) none |

Explanation:

To find the sum of first 10 prime numbers

First 10 prime numbers = 2, 3, 5, 7, 11, 13, 17, 19, 23, 29

Hence, The sum of the first 10 prime numbers is

(2+3+5+7+11+13+17+19+23+29) = **129 (ODD Number).**

A) secant | B) chord |

C) tangent | D) None of the above |

Explanation:

A segment with endpoints on the circle is a chord. The longest chord of a circle is a diameter of the circle.

A) 19/6 | B) 32/4 |

C) 16/3 | D) None of the above |

A) 9 | B) 16 |

C) 22 | D) 36 |

Explanation:

In the given series 1 4 9 16 22 36

1 = 1 x 1

4 = 2 x 2

9 = 3 x 3

16 = 4 x 4

25 = 5 x 5 (Not 22)

36 = 6 x 6

Hence, the odd man in the series is 22.

A) Rs. 14,400 | B) Rs. 15,600 |

C) Rs. 14,850 | D) Rs. 15,220 |

Explanation:

Let the required Sum = Rs.S

From the given data,

1008 = [(S x 11 x 5)/100] - [(S x 8 x 6)/100]

=> S = Rs. 14,400.

A) 68 | B) 36 |

C) 20 | D) 16 |

Explanation:

The given number series is **8, 16, 20, 36, 68**

8

8 x 2 - 4 = 12 (**NOT 16**)

12 x 2 - 4 = 20

20 x 2 - 4 = 36

36 x 2 - 4 = 68

Hence, the odd man in the given series is **16.**