Quantitative Aptitude - Arithmetic Ability Questions

Q:

Direction: What should come in the place of question mark (?) in the following number series?

2, 3, 6, 15, 45, ?

A) 90 B) 135
C) 157.5 D) 200
 
Answer & Explanation Answer: C) 157.5

Explanation:

The pattern followed is *1.5 , * 2 , *2.5 , *3 , *3.5

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Filed Under: Numbers
Exam Prep: AIEEE , Bank Exams , GATE

0 29487
Q:

Find the appropriate relation for quantity 1 and quantity 2 in the following question:

Quantity I: the unit digit in (6817)754

Quantity II: the unit digit in (365×659×771)

A) Quantity I > Quantity II B) Quantity I < Quantity II
C) Quantity I ≥ Quantity II D) Quantity I ≤ Quantity II
 
Answer & Explanation Answer: A) Quantity I > Quantity II

Explanation:
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1 29467
Q:

If 76 is divided into four parts proportional to 7, 5, 3, 4, then the smallest part is:

A) 12 B) 15
C) 16 D) 19
 
Answer & Explanation Answer: A) 12

Explanation:

Given ratio = 7 : 5 : 3 : 4, Sum of ratio terms = 19.

Smallest part =  (76*3/19)  = 12

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Filed Under: Ratios and Proportions

73 29451
Q:

The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 12%, then the cost price of the article is :

A) Rs. 560 B) Rs. 530
C) Rs. 500 D) Rs. 514
 
Answer & Explanation Answer: C) Rs. 500

Explanation:

110% of S.P. = Rs. 616

S.P. = (616 x 100)/110 = Rs. 560

C.P = (110 x 560)/112 = Rs. 500

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

65 29348
Q:

Find the appropriate relation for quantity1 and quantity2 in the following question:

Quantity 1: In an examination, Ankita scored 35 marks less than Puneeta. Puneeta scored 65 more marks than Meenakshi. Rakhi scored 115 marks, which is 20 marks more than Meenakshi's. Simpy scored 108 marks less than the maximum marks of the test. What approximate percentage of marks did Simpy score in the examination, if she got 67 marks more than Ankita?

Quantity 2: The length of a rectangle is increased by 60%. By what percent would the width have to be decreased to maintain the same area?

A) Quantity1 < Quantity2 B) Quantity1 ≤ Quantity2
C) Quantity1 ≥ Quantity2 D) Quantity1 > Quantity2
 
Answer & Explanation Answer: D) Quantity1 > Quantity2

Explanation:

Quantity1-
Rakhi’s marks= 115
Meenakshi’s marks= 115 - 20 = 95
Puneeta’s marks= 95 + 65= 160
Ankita’s marks=160 - 35= 125
Simpy’s marks= 125+ 67= 192
Total maximum marks= 192 + 108= 300
Required percentage marks of Simpy
192300×100=64%
Quantity2-
Let length and breadth be 100.

After increase in length it become 160, then
reduction in breadth be ‘x’
Now, 160*x= 100*100
Hence, x = 10000160=62.5

100-62.5=37.5%

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2 29316
Q:

Entry fee in an exhibition was Rs. 1. Later, this was reduced by 25% which increased the sale by 20%. The percentage increase in the number of visitors is :

A) 20 % B) 40 %
C) 60 % D) 80 %
 
Answer & Explanation Answer: C) 60 %

Explanation:

Let the total original sale be Rs. 100. Then, original number of visitors = 100.

New number of visitors  =  120/0.75 = 160.

Increase % = 60 %.

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Filed Under: Percentage

95 29244
Q:

A and B can do a piece of work in 40 and 50 days. If they work at it an alternate days with A beginning in how many days, the work will be finished ?

Answer

(A+B)'s two days work = 140+150=9200 


 


Evidently, the work done by A and B duing 22 pairs of days 


 


 i.e in 44 days = 22×9200=198200 


 


Remaining work = 1-198200= 1/100


 


 Now on 45th day A will have the turn to do 1/100 of the work and this work A will do in 40×1100=25


 


 Therefore,  Total time taken = 4425daya

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Subject: Time and Work
Job Role: Bank PO

72 29236
Q:

The average temperature of the town in the first four days of a month was 58 degrees. The average for the second, third, fourth and fifth days was 60 degrees. If the temperatures of the first and fifth days were in the ratio 7 : 8, then what is the temperature on the fifth day ?

A) 62 degrees B) 64 degrees
C) 65 degrees D) 66 degrees
 
Answer & Explanation Answer: B) 64 degrees

Explanation:

Sum of temperatures on 1st, 2nd, 3rd and 4th days = (58 * 4) = 232 degrees ... (1)

Sum of temperatures on 2nd, 3rd, 4th and 5th days - (60 * 4) = 240 degrees  ....(2)

Subtracting (1) From (2), we get :

Temp, on 5th day  - Temp on 1st day  = 8 degrees.

Let the temperatures on 1st and 5th days be 7x and 8x degrees respectively.

Then, 8x - 7x = 8 or x = 8.

Temperature on the 5th day = 8x = 64 degrees.

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Filed Under: Average

56 29230