6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A person sold two cows each for Rs.9900. If he gained 10% on one and lost 20% on the other, then which of the following is true?

A) He Gained Rs. 200	B) He lost Rs. 200
C) He neither gained nor lost	D) None of the above

Answer & Explanation Answer: D) None of the above

Explanation:

The CP of profitable cow = 9900/1.1 = 9000

and profit = Rs. 900

The CP of loss yielding cow = 9900/0.8 = 12375

and loss = Rs. 2475

so, the net loss = 2475 - 900 = 1575

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

26 19953

Q:

A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present ?

A) 36 yrs	B) 38 yrs
C) 40 yrs	D) 42 yrs

Answer & Explanation Answer: C) 40 yrs

Explanation:

Let the mother's present age be x years.

Then, the person's present age = 2/5 x years.

(2x/5 + 8) = 1/2 (x + 8)

2(2x + 40) = 5(x + 8) => x = 40.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

26 19953

Q:

What is the probability of getting at least one six in a single throw of three unbiased dice?

A) 1/36	B) 91/256
C) 13/256	D) 43/256

Answer & Explanation Answer: B) 91/256

Explanation:

Find the number of cases in which none of the digits show a '6'.

i.e. all three dice show a number other than '6', 5×5×5=125 cases.

Total possible outcomes when three dice are thrown = 216.

The number of outcomes in which at least one die shows a '6' = Total possible outcomes when three dice are thrown - Number of outcomes in which none of them show '6'.

=216−125=91

The required probability = 91/256

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Filed Under: Probability

27 19949

Q:

For any two numbers m , n ; (m+n) : (m-n) : mn = 7: 1: 60 . Find the value of 1/m : 1/n

A) 4:3	B) 8:7
C) 3:4	D) 7:8

Answer & Explanation Answer: C) 3:4

Explanation:

$\frac{m + n}{m - n} = \frac{7 x}{x} \Rightarrow \frac{m}{n} = \frac{4 x}{3 x}$

Again $m n = 12 x^{2}$

and mn =60x

so, $60 x = 12 x^{2} \Rightarrow x = 5$

=> m= 20 and n= 15

Hence, $\frac{1}{m} : \frac{1}{n} = \frac{1}{20} : \frac{1}{15} = 3 : 4$

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Filed Under: Ratios and Proportions

47 19947

Q:

The ratios of areas of two squares, one having its diagonal double than the other is

A) 2:1	B) 2:3
C) 3:1	D) 4:1

Answer & Explanation Answer: D) 4:1

Explanation:

ratio = $\frac{(1 / 2) \times {(2 d)}^{2}}{\frac{1}{2} d^{2}} = 4 : 1$

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

49 19922

Q:

The present average age of a family of five members is 26 years. If the present age of the youngest member in the family is ten years, then what was the average age of the family at the time of the birth of the youngest member ? (Assume no death occurred in the family since the birth of the youngest)

A) 19 years	B) 16 years
C) 18 years	D) 20 years

Answer & Explanation Answer: D) 20 years

Explanation:

Present total age of the members = 26(5) = 130 years.

Present age of the youngest member = 10 years

Present total age of the remaining four members = 130 -10 = 120 years

Their average age at the time of the birth of the youngest member = $\frac{[120 - (4 \times 10)]}{4}$ = 30 - 10 = 20 years.

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Filed Under: Problems on Ages
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

19 19913

Q:

A boatman can row 3 km against the stream in 20 minutes and return in 18 minutes. Find the rate of current ?

A) 1/3 kmph	B) 2/3 kmph
C) 1/4 kmph	D) 1/2 kmph

Answer & Explanation Answer: D) 1/2 kmph

Explanation:

Speed in upstream = Distance / Time = 3 x 60/20 = 9 km/hr.

Speed in downstream = 3 x 60/18 = 10 km/hr

Rate of current = (10-9)/2 = 1/2 km/hr.

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

32 19894

Q:

The average of five numbers is 27. If one number is excluded, the average becomes 25. The excluded number is :

A) 25	B) 35
C) 45	D) 55

Answer & Explanation Answer: B) 35

Explanation:

Excluded number = (27 x 5) - (25 x 4) = 135 - 100 = 35.

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Filed Under: Average

31 19891

Quantitative Aptitude - Arithmetic Ability Questions

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