Quantitative Aptitude - Arithmetic Ability Questions

The third proportional of two numbers p and q is defined to be that number r such that

p : q = q : r.

Here, required third proportional of 10 & 20, and let it be 'a'

=> 10 : 20 = 20 : a

10a = 20 x 20

=> a = 40

Hence, third proportional of 10 & 20 is 40.

Let the required number of bottles be x.

More weavers, More mats (Direct Proportion)

More days, More mats (Direct Proportion)

$$\begin{gathered} weavers 4:8} :4:x \\ days 4:8}:4:x \end{gathered}$$ 

4 x 4 x x = 8 x 8 x 4

=> x = 8*8*44*4

=> x = 16.

Here, k = 7 and l = 28
Therefore, first number = klx100 % of second number = 7/28 x 100% of second number = 25% of second number.

a2b2=225/256

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27 x meters, and

length of the second train = 17 y meters.

(27 x + 17 y) / (x + y) = 23

=> 27 x + 17 y = 23 x + 23 y

=> 4 x = 6 y

=> x/y = 3/2.

loss % = common gain or loss102 %

           = (20/10)x(20/10)% = 4%

Ratio of investments of A, B & C = 2×6+4×6 : 3×12 : 4×12

= 36 : 36 : 48

= 6 : 6 : 8

But given that the annual profit of B is Rs. 3000

=> 6 ratio = 3000

Then for the total annual profit of partners is

20 ratio = 3000 x 20/6 = 10,000.

Sol : Time = Circumference Relative Speed = 60010 = 60 sec.

Actually Arjun has to make a lead of 600 m, because when Arjun will be 600m ahead of Bhishma, they will be together again as a person when completes the total length it starts retracing he same path and thus Arjun and Bhishma can be together again.

Since , they make  a difference of 10 m in 1 second. so, he will create 600m difference in 60 second.