Quantitative Aptitude - Arithmetic Ability Questions

Q:

Courier charges for packages to a certain destination are 65 cents for the first 250 grams and 10 cents for each additional 100 grams or part thereof. What could be the weight in grams of a package for which the charge is $1.55 ?

A) 1155 B) 1145
C) 1040 D) None
 
Answer & Explanation Answer: B) 1145

Explanation:

The weight will be 250g plus (1.55 - 0.65)/0.10 units of 100g

250 + 900 = 1150

This is the maximum weight that can be sent at that price. But, weights exceeding

250 + 800 will also get charged this amount (that is what the ‘part thereof’ implies).

Hence a package weighing 1145 will be charged $1145

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Filed Under: Numbers
Exam Prep: GRE

9 10019
Q:

If Riya's age is four times the age of Siya and if Riya's age is 24 yrs , find the age difference between Riya and Siya ? 

A) 2 yrs B) 12 yrs
C) 18 yrs D) 6 yrs
 
Answer & Explanation Answer: C) 18 yrs

Explanation:

Let Siya's age = x

Then Riya's age = 4x

But given Riya's age = 24

=> 4x = 24 => x = 6

Hence Siya's age = 6 yrs

=> The age difference = 24 - 6 = 18 yrs.

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Filed Under: Problems on Ages
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9 10008
Q:

If 35+125=17.88, then what will be the value of 80+65 =?

A) 13.41 B) 20.46
C) 21.66 D) 22.35
 
Answer & Explanation Answer: D) 22.35

Explanation:

35+125=17.88 35+55=17.88

5=2.235

 

80+65=45+65=105=10×2.235=22.35

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17 10004
Q:

If 4th december 1999 is Monday then what day is 3rd january 2000 ?

A) Sunday B) Monday
C) Tuesday D) Wednesday
 
Answer & Explanation Answer: D) Wednesday

Explanation:

Here from 4th December 1999 to 3rd January 2000,
there is a difference of 30 days.
Number of odd days = 30/7 = 2 odd days

Then no. of odd days = 2 => tuesday and wednesday(from monday).

Hence on 3rd january it is wednesday.

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Filed Under: Calendar
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17 9975
Q:

15th February 2018 is a Thursday. On what day will 18th April 2019 fall?

A) Saturday B) Friday
C) Wednesday D) Thursday
 
Answer & Explanation Answer: A) Saturday

Explanation:
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Filed Under: Calendar
Exam Prep: Bank Exams

67 9963
Q:

A man can row against the current three fourth of a kilometer in 15 min and returns same distance in 10 min, then ratio of his speed to that of current?

A) 5:1 B) 3:1
C) 4:1 D) 2:1
 
Answer & Explanation Answer: A) 5:1

Explanation:

Let the speed of the man in still water = p kmph

Speed of the current = s kmph

Now, according to the questions

(p + s) x 10 = (p - s) x 15

2p + 2s = 3p - 3s

=> p : s = 5 : 1

 

Hence, ratio of his speed to that of current = 5:1.

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Filed Under: Boats and Streams
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24 9944
Q:

Amith can row a boat d km upstream and the same distance downstream in 5 hours 15 minutes. Also, he can row the boat 2d km upstream in 7 hours. How long will it take to row the same distance 2d km downstream for Amith ?

A) 4 hrs 10 min B) 3 hrs 15 min
C) 3 hrs 30 min D) 4 hrs 1 min
 
Answer & Explanation Answer: C) 3 hrs 30 min

Explanation:

Let the speed of boat and stream be x and y kmph respectively.

According to question

d/x+y + d/x-y = 5h 15m or 21/4 hrs ......(i)

and 2d/x-y = 7...... (ii)

From eq. (i) and (ii)

2d/x+y = 7/2

Hence, Amith will take to row 2d km distance downstream in 7/2 hrs

= 3.5 hrs

= 3 hrs 30 min.

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Filed Under: Boats and Streams
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16 9921
Q:

How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction ?

A) 58 sec B) 62 sec
C) 60 sec D) 50 sec
 
Answer & Explanation Answer: D) 50 sec

Explanation:

The distance to be covered = Sum of their lengths = 200 + 300 = 500 m.

Relative speed = 72 -36 = 36 kmph = 36 x 5/18 = 10 mps.

Time required = d/s = 500/10 = 50 sec.

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Filed Under: Problems on Trains
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8 9919