Quantitative Aptitude - Arithmetic Ability Questions

31st Dec, 2011 = (2010 years + Period from 1.1.2011 to 31.12.2011)

Odd days in 2000 years = 0

10 years has 2 leap years + 8 ordinary years.

Number of odd days in 10 years ( 2 x 2 + 8) = 5 odd days.

31st,Dec => complete year of 2011 (non-leap year) = 1 odd day.

Total number of odd days = (0 + 5 + 1) = 6.

Given day is saturday.

In the word 'MATHEMATICS', we treat the vowels AEAI as one letter.

Thus, we have MTHMTCS (AEAI).

Now, we have to arrange 8 letters, out of which M occurs twice, T occurs twice and the rest are different.

Number of ways of arranging these letters = 8!/(2! x 2!)= 10080.

Now, AEAI has 4 letters in which A occurs 2 times and the rest are different.

Number of ways of arranging these letters =4!/2!= 12.

Required number of words = (10080 x 12) = 120960

Substitute sensible numbers and work out the problem. Then change the numbers back to letters. For example if the machine puts 6 caps on bottles in 2 minutes, it will put 6 /2 caps on per minute, or (6 /2) x 60 caps per hour. Putting letters back this is 60c/m.If you divide the required number of caps (b) by the caps per hour you will get time taken in hours. This gives bm/60c

We have to find number of permutations of 4 objects out of 6 objects.

This number is 6P4= 360

Therefore, cards can be sent in 360 ways.

Given = (0.2 * 0.2 + 0.01) / ( 0.1 * 0.1 + 0.02) = (0.04 + 0.01) / (0.01 + 0.02) = 0.05 / 0.03 = 5/3...

Anu = (Raj + 5) + 9

= Raj + 14 -------- (I)

Raj = (Renu - 4) + 7

= Renu + 3 ------- (II)

Raj's age = 19 + 3 = 22 years

After 5 years Anu's age = 22 + 14 + 5 = 41 years

P.W=Rs.100×2310100+15×52 = Rs.1680

More Men, Less Hours {Indirect Proportion}

Less Days, More Hours {Indirect Proportion}

 men15 : 10days12 : 18 ⋮⋮ 6:x

=> 15 * 12 * x = 10 * 18 * 6

=>x = 6