32
Q:

How many of the following numbers are divisible by 132?

264,396,462,792,968,2178,5184,6336

A) 4 B) 5
C) 6 D) 7

Answer:   A) 4



Explanation:

132 = 4 x 3 x 11, So if the number is divisible by all three numbers 4,3 and 11,then the number is divisible by 132 also.
264   => 4,3,11(/)
396   => 4,3,11(/)
462   => 11,3
792   => 4,3,11(/)
968   => 11,4
2178 => 11,3
5184 => 3,4
6336 => 4,3,11(/)
Required number of numbers=4.

Subject: Numbers
Q:

(51 + 52 + 53 + .........+100) is equal to

Answer

51 + 52 + 53 + ...........+ 100


 = (1 + 2 + 3 + .... + 100) - (1 + 2 + 3 + ...... + 50)


 = It is in the form of n(n+1)2 series summation


= n1 = 100 , n2 = 50


=100100+12 - 5050+12


 =  (5050 - 1275) = 3775

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Subject: Numbers Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

292 58079
Q:

On dividing 4150 by a certain number , the quotient is 55 and the remainder is 25, the divisor is

Answer

Divisor = 


           = 

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Subject: Numbers

34 9356
Q:

The total number of prime factors in the expansion

Answer

 


2211 x 75 x 112=> 222 x 75 x 112


 Total number of prime factors is (22+5+2) = 29

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Subject: Numbers Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

4 4692
Q:

The sum of first 45 natural numbers is:

Answer

The sum of n natural numbers 

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Subject: Numbers

57 11679
Q:

What is the simplified result of following the steps below in order?

       1.Add 5y to 2x

       2.Multiply the sum by 3

       3.Substract x+y from the product

A) 5x + 14y B) 5x + 16y
C) 5x + 5y D) None
 
Answer & Explanation Answer: A) 5x + 14y

Explanation:

Step 1 :2x + 5y

Step 2 :3(2x + 5y) = 6x + 15y

Step 3 :(6x + 15y) - (x +y) = 6x + 15y - x - y (watch that last minus sign!)

This gives 5x + 14y

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Filed Under: Numbers
Exam Prep: GRE

5 15481
Q:

If x / y is an integer, which of the following statements need NOT always be true?

A) both x and y are integers B) only x is a integer
C) both are negative D) none
 
Answer & Explanation Answer: A) both x and y are integers

Explanation:

In case (A), x and y could, for example, both be equal fractions and x/y would be an integer.

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Exam Prep: GRE

2 2922
Q:

Courier charges for packages to a certain destination are 65 cents for the first 250 grams and 10 cents for each additional 100 grams or part thereof. What could be the weight in grams of a package for which the charge is $1.55 ?

A) 1155 B) 1145
C) 1040 D) None
 
Answer & Explanation Answer: B) 1145

Explanation:

The weight will be 250g plus (1.55 - 0.65)/0.10 units of 100g

250 + 900 = 1150

This is the maximum weight that can be sent at that price. But, weights exceeding

250 + 800 will also get charged this amount (that is what the ‘part thereof’ implies).

Hence a package weighing 1145 will be charged $1145

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Filed Under: Numbers
Exam Prep: GRE

9 8819
Q:

3x + y = 19  and x + 3y = 1. Find the value of 2x + 2y

A) 20 B) 18
C) 11 D) 10
 
Answer & Explanation Answer: D) 10

Explanation:

To solve a pair of simultaneous equations such as those given we can add or subtract them.

Adding we get 4x + 4y = 20

Therefore 2x + 2y = 10

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Filed Under: Numbers
Exam Prep: GRE

10 9429