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Q:

Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of the father of the younger boy. Similarly, we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divide the figure by 2, we get the age of the mother of the younger boy. The mother of the younger boy is younger than his father by 3 years. Then, what are the ages of elder and younger boys ?

A) E = 15 & Y = 3 B) E = 14 & Y = 12
C) E = 40 & Y = 22 D) E = 4 & Y = 2

Answer:   D) E = 4 & Y = 2



Explanation:

Let the the age of the elder boy = E

 

Let the the age of the younger boy = Y

 

Given that Y = cube root of EY

 


=> Y3 = EY => E = Y2 .....(1)
By the condition of number replacement the age of the father is YE

 

The Mother's age = EY/2

 

But she is 3 years less than father => EY/2 + 3 = YE
2YE = EY + 6 ......(2)

 

Then now from the given options we can identify which satisfies the all the conditions.

 

Here Y =2 and E = 4 satisfies all the conditions.

Q:

The age of X is 2/3 rd that of Y. After 6 years X will be 46 years old. the present age of Y is?

A) 40 B) 56
C) 60 D) 100
 
Answer & Explanation Answer: C) 60

Explanation:

X= 2/3Y 

=> Y= 3/2X

 

Aage of X after 6 years = 46 years

 

So present age of X = 46-6 = 40 years

 

Now, present age of Y = 3/2 * 40 = 60 years.

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0 62
Q:

Ishikha got married 9 years ago. Today her age is 4/3 times her age at the time of marriage. At present her daughter’s age is one-sixth of her age. What was her daughter’s age three years ago?

A) 4 years B) 3 years
C) 2 years D) 1 year
 
Answer & Explanation Answer: B) 3 years

Explanation:

Let Ishika and her daughter present ages be p and q

From the given data,

p = 4/3(p - 9)

=> p = 36 years

 

Hence, Ishika's present age = 36 years and

her daughter's present age = 1/6 x 36 = 6 years

 

Now, required her daughter’s age three years ago = 6 - 3 = 3 years.

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0 105
Q:

Manogna's father was 38 years of age when she was born while her mother was 36 years old when her brother, 4 years younger than her, was born. What is the difference between the ages of her parents?

A) 2 years B) 4 years
C) 6 years D) 8 years
 
Answer & Explanation Answer: C) 6 years

Explanation:

From the given data,

Manogna’s age be 0 when she was born.

Her father’s age = 38 years

Her mother’s age when Manogna’s brother who is 4 years younger to her was born = 36 years

=> Manogna’s mother age when Manogna was born = 36 - 4 = 32 years

 

Hence, the difference between the ages of Manogna’s parents = 38 - 32 = 6 years.

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0 51
Q:

The difference between the present ages of Avanthi and Kapil is 9 years. After 7 years, Kapil’s age is twice of Avanthi’s age. What will be Kapil’s age after 4 years?

A) 15 B) 16
C) 18 D) 20
 
Answer & Explanation Answer: A) 15

Explanation:

Let the present ages of Kapil and Avanthi be K & A

Given difference in their ages = K - A = 9 years ...........(1)

After 7 years, K + 7 =  2(A + 7) ......(2)

K + 7 = 2A + 14

K - 2A = 7 ............(3)

K - A = 9 ....(1)

From (1) & (3),

-A = -2

=> A = 2 years

=> K = 9 + 2 = 11 years

 

Required, age of Kapil after 4 years = 11 + 4 = 15 years.

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0 230
Q:

Karthik is now 32 years old and his son is 7 years old. In how many years will Karthik be twice as old as the son?

A) 18 B) 25
C) 7 D) 15
 
Answer & Explanation Answer: A) 18

Explanation:

Given Karthik’s age = 32 years

Karthik’s son age = 7 years

Difference between their ages = K - S = 32 - 7 = 25 years ….(1)

Now, required K = 2S ……(2)

Put (2) in (1)

2S - S = 25

=> S = 25 years

Hence, at the age of 25 years of Karthik’s son, Karthik will be twice as his son’s age.

25 - 7 = 18 years

 

Therefore, after 18 years the father be twice as old as the son.

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1 334
Q:

The ages of Sunitha and Pranitha are 40 years and 60 years, respectively. How many years before the ratio of their ages was 3 : 5?

A) 10 years B) 15 years
C) 18 years D) 24 years
 
Answer & Explanation Answer: A) 10 years

Explanation:

Given the ages of Sunitha and Pranitha are 40 years and 60 years.

Let before 'm' years, their ages be in the ratio of 3 : 5

ATQ,

40-m60-m = 35

=> 200 - 5m = 180 - 3m

=>2m = 20

=> m = 10 years.

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3 488
Q:

5 years ago, the mother's age was 3 times of her son's age. 5 years hence, the ratio between the ages of mother and the son becomes 11:5. Find the mother's present age?

Answer

Let the present age's of mother be 'M' and that of her son be 'S'.


According to the given data in the question,


M - 5 = 3(S - 5)


F - 3S = -10  ...............(1)


Then given ,


M + 5 : S + 5 = 11 : 5 


=> 5M - 11S = 30 ..............(2)


 


From (1) & (2), we get


S = 20


Then by substituting S = 20 in (1) or (2), we get


M = 50.


 


Hence, the present age of mother is M = 50 years.

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5 490
Q:

The age of Sohail, Afzal and Bilal are 17,16 and 12 respectively. If the age of Aslam also included the average of the ages is increased by 5. What is the age of Aslam?

A) 32 B) 33
C) 34 D) 35
 
Answer & Explanation Answer: D) 35

Explanation:

Given S = 17 yrs

A = 16 yrs

B = 12 yrs

Average = 17 + 16 + 12/3 = 15 yrs

Given if Aslam added to them, their average increases by 5

=> Average of 4 members = 20

Let the age of Aslam be 'x'

Then, 

17 + 16 + 12 + x /4 = 20

=> x = 80 - 45

=> x = 35. 

 

Hence, the age of Aslam is 35 yrs.

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