# Job Roles

A) 14.69 cm | B) 15.69 cm |

C) 18.65 cm | D) 16.42 cm |

Explanation:

Draw the two chords as shown in the figure. Let O be the center of the circle. Draw OC

perpendicular to both chords. That divides the two chords in half.

So CD = 10 and AB = 14. Draw radii OA and OD, both equal to radius r.

We are given that BC = 5, the distance between the two chords. Let

OB = x.

We use the Pythagorean theorem on right triangle ABO

AO² = AB² + OB²

r² = 14² + x²

We use the Pythagorean theorem on right triangle DCO

DO² = CD² + OC²

We see that OC = OB+BC = x+5, so

r² = 10² + (x+5)²

So we have a system of two equations:

r² = 14² + x²

r² = 10² + (x+5)²

Since both left sides equal r², set the right sides

equal to each other.

14² + x² = 10² + (x+5)²

196 + x² = 100 + x² + 10x + 25

196 = 125 + 10x

71 = 10x

7.1 = x

r² = 14² + x²

r² = 196 + (7.1)²

r² = 196 + 50.41

r² = 246.41

r = √246.41

r = 15.69745202 cm

An Android Intent is an abstract description of an operation to be performed. It can be used with startActivity to launch an Activity, broadcastIntent to send it to any interested BroadcastReceiver components, and startService(Intent) or bindService(Intent, ServiceConnection, int) to communicate with a background Service.The intent itself, an Intent object, is a passive data structure holding an abstract description of an operation to be performed.

Android provides many ways of storing data of an application. One of this way is called Shared Preferences. Shared Preferences allow you to save and retrieve data in the form of key,value pair.

In order to use shared preferences, you have to call a method getSharedPreferences() that returns a SharedPreference instance pointing to the file that contains the values of preferences.

A) Japan | B) Russia |

C) China | D) India |

Explanation:

China's amphibian aircraft, which is stated to be the world's largest, has successfully passed engine tests and is expected to make its maiden flight in the first half of the year 2017.

A) 14.69 cm | B) 29.39 cm |

C) 18.65 cm | D) 22.21 cm |

Explanation:

Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of dia 12 cms

As speed is same, area of cross sections should be same.

Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12

i.e

Here R = R and R1 = 12/2 = 6

R = 14.696

=> D = X = 14.696 x 2 = 29.3938 cm.

A) 264 | B) 284 |

C) 215 | D) 302 |

Explanation:

Let the number be 'x'. Then, from given data

x/2 + x/3 + x/4 = x+22

13x/12 = x+22

x = 264