Aptitude and Reasoning Questions

Q:

The first 8 alphabets are written down at random. what is the probability that the letters b,c,d,e always come together ?

A) 1/7 B) 8!
C) 7! D) 1/14
 
Answer & Explanation Answer: D) 1/14

Explanation:

The 8 letters can be written in 8! ways.
n(S) = 8!
Let E be the event that the letters b,c,d,e always come together when the first 8 alphabets are written down.
Now the letters a, (bcde), f, g and h can be arranged in 5! ways.
The letters b,c,d and e can be arranged themselves in 4! ways.
n(E) = 5! x 4!
Now, the required P(E) = n(E)/n(S) = 5! x 4!/8! = 1/14
Hence the answer is 1/14. 

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Filed Under: Probability
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15 8576
Q:

A fraction becomes 2/3 when 1 is added to both, its numerator and denominator .And , it becomes 1/2 when 1 is subtracted from both the numerator and denominator. What is the fraction?

Answer

Let required fraction be  then 


           ............. (i)


and          ............ (ii)


Solving (i) and (ii) we get x=3, y=5


\inline \therefore Required fraction = 

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Q:

A sector of 120, cut out from a circle, has an area of 667cm2. Find the radius of the circle ?

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: C) 3

Explanation:

Let the radius of the circle be r cm. Then, 

 

120360πr2=667 

 

r2=667*722*3 

 

r=3.

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Filed Under: Area
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2 8574
Q:

Three graziers A,B and C rent a piece of pasture for a month. A puts in 27 cattle for 19 days, B 21 for 17 days and C 24 for 23 days. If at the end of the month the rent amount to Rs.237, how much ought to be paid by each.

Answer

A's cattle = 27 x 19 = 513


B's cattle = 21 x 17 = 357


C's cattle = 24 x 23 = 552


Ratio of cattle = 513 : 357 : 552


                    = 171 : 119 : 184


 


payment to be made by A = \inline 237\times \frac{171}{474}


                                     = Rs.85.50


payment to be made by B = \inline 237\times \frac{119}{474}


                                     = Rs.59.50


payment to be made by C = \inline 237\times \frac{184}{474}


                                     = Rs.92

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Subject: Partnership

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Q:

854*854*854-276*276*276854*854+854*276+276*276=?

A) 546 B) 578
C) 607 D) None of these
 
Answer & Explanation Answer: B) 578

Explanation:

Given exp . is like this 854*854*854-276*276*276854*854+854*276+276*276=?

 

so ans = 854 - 276 = 578

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Filed Under: Numbers

3 8562
Q:

Find the length of a train if it takes 10 seconds to cross a pole and double of this time to cross a platform of length 200 mts ?

A) 180 mts B) 190 mts
C) 200 mts D) 210 mts
 
Answer & Explanation Answer: C) 200 mts

Explanation:

Let the length of the train be 'L' mts

let the speed of the train be 'S' m/s

Given it crosses a pole in 10 sec=> L/S = 10 ......(1)
Given it takes 20 sec (double of pole) to cross a platform of length 200 mts

=> (L + 200)/S = 20

=> L/S + 200/S = 20

But from (1) L/S = 10

=> 200/S = 20 - 10

=> S = 20 m/s

Then, from (1)

=> L = 10 x 20 = 200 mts.

Hence, the length of the train = 200 mts.

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Filed Under: Problems on Trains
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12 8561
Q:

In how many ways can you choose one or more of 12 different candies?

A) 4054 B) 4050
C) 4095 D) 4059
 
Answer & Explanation Answer: C) 4095

Explanation:

Each candy can be dealt with in two ways.It can be chosen or not chosen.This will give 2 possibilites for the first candy, 2 for the second, and so on.by multiplying the cases together we get 212. Since the case of no candy being selected is not an option, we have to subtract 1 from our answer.

 

Therefore,there are 212- 1 = 4095 ways of selecting one or more candies

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0 8560
Q:

Ajay who is a King, at his eleventh hour, called his three queens and distributed his gold in the following way: He gave 50% of his wealth to his first wife, 50% of the rest to his second wife and again 50% of the rest to his third wife. If their combined share is worth1,30,900 kilograms of gold, find the quantity of gold King Ajay was having initially?

A) 153145 kgs B) 147890 kgs
C) 152400 kgs D) 149600 kgs
 
Answer & Explanation Answer: D) 149600 kgs

Explanation:

Let the total quantity of gold be p kgs.

According to the question,

50% of p + 25% of p + 12.5% of p = 130900

87.5% of p = 130900

p = 130900 x 100/87.5  = 149600 kgs.

 

Therefore, the initial gold quantity that king has = p = 149600 kgs.

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