5555+ Aptitude and Reasoning Questions, Answers With Explanation

Q:

Two trains start from same place at same time at right angles to each other. Their speeds are 36km/hr and 48km/hr respectively. After 30 seconds the distance between them will be ?

A) 900 mts	B) 300 mts
C) 250 mts	D) 500 mts

Answer & Explanation Answer: D) 500 mts

Explanation:

Using pythagarous theorem,
distance travelled by first train = 36x5/18x30 = 300m
distance travelled by second train = 48x5/18x30 = 400m
so distance between them =√( 90000 + 160000) = √250000 = 500mts.

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Filed Under: Time and Distance
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8 7224

Q:

7 years ago, the ratio of the ages of Anirudh to that of Bhavana, was 7:9. Chandhu is 12 years older than Anirudh and 12 years younger than Bhavana. What is Chandhu's present age?

A) 91 years	B) 115 years
C) 103 years	D) Can't be determined

Answer & Explanation Answer: C) 103 years

Explanation:

Let present Anirudh's age be 'A' and Bhavana's age be 'B'

Given seven years, their ratio is 7:9

=> A-7 : B-7 = 7 : 9

=> 9A - 7B = 14 .......(1)

And given,

Chandhu is 12 years older than A nad 12 years younger than B

=> C = A + 12....(2)

=> B = C + 12

=> B = A + 12 + 12 .....(From (2))

=> B = A + 24 ....(3)

Put (3) in (1)

9A - 7(A+24) = 14

9A - 7A - 168 = 14

2A = 182

=> A = 91 years

=> C = A + 12 = 91 +12 = 103 years.

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Filed Under: Problems on Ages
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9 7222

Q:

(10.3 * 10.3 * 10.3 + 1)/(10.3 * 10.3 - 10.3 + 1) is :

A) 11.3	B) 12.3
C) 13.3	D) 14.3

Answer & Explanation Answer: A) 11.3

Explanation:

a^3 + b^3 = (a+ b) * (a^2 + b^2 - ab)

[ (10.3)^3 + (1)^3 ] / [(10.3)^2 + (1)^2 - (1 * 10.3)]

=> a + b = 10.3 + 1 = 11.3

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Filed Under: Decimal Fractions

6 7220

Q:

In the last month the company decided to increase the cost of its mixer by 10 percent. What is the present price of the mixer?

I. The cost of mixer and juicer together was Rs 2850 a month ago.

II. The amount of 10% increase on the mixer comes to Rs 220.

A) If the data in statement I alone are sufficient to answer the question	B) If the data in statement II alone are sufficient answer the question
C) If the data either in I or II alone are sufficient to answer the question;	D) If the data even in both the statements together are not sufficient to answer the question

Answer & Explanation Answer: B) If the data in statement II alone are sufficient answer the question

Explanation:

The present price of the mixer can he calculated from statement II as follows

Let the earlier price be Rs x.

Then, 10% of x = 220 or x = 2200. Present price = Rs (2200 + 220) = Rs 2420.

So, only II is needed.

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Filed Under: Data Sufficiency

5 7215

Q:

A merchant commences with a certain capital and gains annually at the rate of 30 per cent. At the end of 2 years he has worth Rs 10,000. What was the original capital?

A) Rs. 4987	B) Rs. 5148
C) Rs. 5917	D) Rs. 6254

Answer & Explanation Answer: C) Rs. 5917

Explanation:

Let the Original capital amount be Rs. P

Given after 2 years the amount is Rs. 10000

Rate of interest = 30%

According to the question,

$P x \frac{130}{100} x \frac{130}{100} = 10000 = > P = \frac{1000000}{169} = 5917$

Therefore, the capital amount P = Rs. 5917

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Filed Under: Percentage
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6 7207

Q:

Choose the missing terms out of the given alternatives ADVENTURE,DVENTURE, DVENTUR, ? , VENTU

A) VENTURE	B) VENTUR
C) DVENT	D) DVENTU

Answer & Explanation Answer: B) VENTUR

Explanation:

one of the letter from beginning and one of the letter from the end of a term are removed, one by one, alternate steps

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Filed Under: Number Series

22 7203

Q:

Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it?

___ utt ___ tt ___ ttu ___

A) t t u t	B) t u t t
C) t u u t	D) t t t u

Answer & Explanation Answer: C) t u u t

Explanation:

t, u, u and t.

The sequence is : tut tut tut tut.

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Filed Under: Alphabet Test
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8 7201

Q:

The Value of $[\log (\tan (1^{0})) + \log (\tan (2^{0})) + \dots \dots + \log (\tan (89^{0}))]$ is

A) -1	B) 0
C) 1/2	D) 1

Answer & Explanation Answer: B) 0

Explanation:

$= [\log \tan (1^{0}) + \log \tan (89^{0})] + [\log \tan (2^{0}) + \log \tan (88^{0})] + \dots \dots + [\log \tan (45^{0})]$

$= \log [\tan (1^{0}) \times \tan (89^{0})] + \log [\tan (2^{0}) \times \tan (88^{0})] + \dots \dots + \log (1)$

$[∵ \tan (90 - θ) = c o t θ a n d \tan (45^{0}) = 1]$

= log 1 + log 1 +.....+log 1

= 0.

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Filed Under: Logarithms
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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27 7198

Aptitude and Reasoning Questions

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