Aptitude and Reasoning Questions

Q:

If wall is called window, window is called door, door is called floor, floor is called roof and roof is called ventilator, What will a person stand on ?

A) Window B) Wall
C) Floor D) Roof
 
Answer & Explanation Answer: D) Roof

Explanation:

A person will stand on the floor and floor is called roof. So, a person will stand on the roof

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Filed Under: Coding and Decoding

26 6295
Q:

A person lends Rs. 300 to A at 4% and Rs.540 to B at 6% for the same time. if the total amount that he gets at the end is Rs. 1032. What is the time?

Answer

Money lent to A+B = (300 + 540) = Rs. 840 


Amount received = Rs. 1032 


Interest received = Rs. 1032 - Rs.840 = Rs. 192


 


Interest on Rs. 300 lent to A for 1 year = 300×1×4100 = Rs. 12 


 


Interest on Rs.540 lent to B for 1 year = 540×6×1100 = Rs. 36 


 


 


Total yearly interest = Rs.(12+36) = Rs.48 


If interest is Rs. 48, time = 1 year 


If interest is Rs. 192, time =  192/48 = 4 years 

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Subject: Simple Interest Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

14 6289
Q:

If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to

A) 55/601 B) 601/55
C) 11/120 D) 120/11
 
Answer & Explanation Answer: C) 11/120

Explanation:

Let the numbers be a and b . Then, a+b =55 and ab = 5 x 120 = 600.

 

Therefore, Required sum = 1a+1b=a+bab=55600=11120

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Filed Under: HCF and LCM

7 6288
Q:

There are 1650 students in a college. The difference between the number of boys and girls in the college is 400. What is the percentage of girls in the college ?

A) 49 B) 34
C) 43 D) 38
 
Answer & Explanation Answer: D) 38

Explanation:

Let no. of boys be 'B' and no. of girls be 'G'

Here from given data,

B + G = 1650 .....(1)

B - G = 400 .....(2)

From (1) & (2), we get

2B = 2050

=> B = 1025

=> G = 1650 - 1025 = 625

Hence, the % of girls = 625 x 100/1650

=> 38% (approx).

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

4 6287
Q:

If in the given word VITREOUS all the constants are first arranged alphabetically, and then all the vowels are arranged alphabetically, which letter will be second to the right of fourth  from the left?

A) S B) T
C) I D) E
 
Answer & Explanation Answer: C) I

Explanation:

The given word is VITREOUS. Of which , TRSV are the consonants and IEOU are the vowels. Now, after making the changes as given in the question  we get following arrangment: RSTVEIOU.

Again from precalculation, we know that second to the right of fourth  from the left means (2+4=) 6th from the left. i.e I

 

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Filed Under: Alphabet Test

5 6278
Q:

The number of signals that can be generated by using 5 differently coloured flags, when any number of them may be hoisted at a time is:

A) 235 B) 253
C) 325 D) None of these
 
Answer & Explanation Answer: C) 325

Explanation:

Required number of signals = 5P1 + 5P2 + 5P3 + 5P4 + 5P5

= 5 + 20 + 60 + 120 + 120 = 325

 

 

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Filed Under: Permutations and Combinations
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

4 6277
Q:

The Number of times the digit 8 will be written when listing the integers from 1 to 1000 is :

A) 100 B) 200
C) 300 D) 400
 
Answer & Explanation Answer: C) 300

Explanation:

 Since 8 does not occur in 1000, we have to count the number of times 8 occurs when we list the integers from 1 to 999. Any number between 1 and 999 is of the form xyz, where 0x,y,z9.

 

Let us first count the numbers in which 8 occurs exactly once.

 

Since 8 can occur atone place in 3C1ways. There are 3 x 9 x 9  such numbers.

 

Next, 8 can occur in exactly two places in 3C2×9 such numbers. Lastly, 8 can occur in all three digits in one number only.

  

Hence, the number of times 8 occur is 

 1×3×92+2×3×9+3×1 = 300

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2 6275
Q:

Three fair coins are tossed simultaneously. Find the probability of getting more heads than the number of tails

A) 2 B) 7/8
C) 5/8 D) 1/2
 
Answer & Explanation Answer: D) 1/2

Explanation:

S = { HHH, HHT, HTH, HTT, THH, THT, TTH, TTT }

=> n(S) = 8

E = { HHH, HHT, HTH, THH }

=> n(E) = 4

P(E) = 4/8 = 1/2

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Filed Under: Probability

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