Aptitude and Reasoning Questions

Q:

The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:

A) 625 B) 635
C) 645 D) 655
 
Answer & Explanation Answer: A) 625

Explanation:

Let the sum be Rs. x. Then

C.I=x[1+4/100)^2-x]=[626/675x-x]

S.I=x^2/25

C.I-S.I=1

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Filed Under: Compound Interest
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0 6067
Q:

74.99% of 1299 + 8.98% of 1899 = ? 

A) 1378 B) 1301
C) 1212 D) 1197
 
Answer & Explanation Answer: C) 1212

Explanation:

74.99% of 1299 + 8.98% of 1899 = ? 

? = 75 x 1400100 + 9 x 1800100 ? = 1050 + 162? = 1212.

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9 6066
Q:

 What is the rate of compound interest?
I. The principal was invested for 4 years.
II. The earned interest was Rs. 1491.

A) I alone sufficient while II alone not sufficient to answer B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer D) Either I or II alone sufficient to answer
 
Answer & Explanation Answer: D) Either I or II alone sufficient to answer

Explanation:

 

 

Let Principal = Rs. P and Rate = R% p.a. Then,

 

Amount= Rs.P1+R1004

 

 C.I = P1+R1004-1

 P1+R1004-1=1491

 

Clearly, it does not give the answer

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Filed Under: Compound Interest
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0 6065
Q:

On Rs. 3500 invested at a simple interest rate of 7 per cent per annum, Rs. 500 is obtained as interest in certain years. In order to earn Rs. 800 as interest on Rs. 4900 in the same number of years, what should be the rate of simple interest?

A) 8% B) 7.5%
C) 9% D) 8.5%
 
Answer & Explanation Answer: A) 8%

Explanation:

From the given data,

3500x7xt/100 = 500

=> t = 100/49 years

Now, in the second case

The interest per year = 49/100 x 800 = 392

 => 4900 x 1 x r/100 = 392

=> r = 8%

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Filed Under: Simple Interest
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10 6062
Q:

Two equal sums were lent, one at the rate of 11% per annum for five years and the other at the rate of 8% per annum for six years, both under simple interest. If the difference in interest accrued in the two cases is Rs 1008. Find the sum?

A) Rs. 14,400 B) Rs. 15,600
C) Rs. 14,850 D) Rs. 15,220
 
Answer & Explanation Answer: A) Rs. 14,400

Explanation:

Let the required Sum = Rs.S

 From the given data,

 1008 = [(S x 11 x 5)/100] - [(S x 8 x 6)/100]

 => S = Rs. 14,400.

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18 6060
Q:

Two dice are rolled simultaneously. Find the probability of getting a total of 9.

A) 1/3 B) 1/9
C) 8/9 D) 9/10
 
Answer & Explanation Answer: B) 1/9

Explanation:

S = { (1, 1), (1, 2), (1, 3), (1, 4),(1, 5), (1, 6), (2, 1), (2, 2),.........(6, 5), (6, 6) }

=> n(S) = 6 x 6 = 36

E = {(6, 3), (5, 4), (4, 5), (3, 6) }

=> n(E) = 4

Therefore, P(E) = 4/36 = 1/9

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8 6053
Q:

A jar can 20 litre milk. From the jar, 4 litres milk was taken out and replaced with an equal quantity of water. If 4 litres of the newly formed mixture is taken out of the can, then what is the final quantity of milk left in the can?

A) 14.5 lit B) 12.8 lit
C) 11.6 lit D) 10.46 lit
 
Answer & Explanation Answer: B) 12.8 lit

Explanation:

This can be solved as

 

20 1 - 4202  =  20 1 - 152= 20452= 20 1625= 645= 12.8

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11 6052
Q:

The total simple interest earned on a sum of money increases by Rs. 600 when the rate of interest increases by 2% per annum. If the investment was made for 5 years, find the sum of money that was invested ?

A) Rs. 6000 B) Rs. 5550
C) Rs. 7500 D) Rs. 6580
 
Answer & Explanation Answer: A) Rs. 6000

Explanation:

Let the sum invested be Rs. P

Let the rate of interest be R% per annum

=> Interest earned for 5 years = (P x 5 x R/100) = PR/20

Now, given that the interest earned increased by Rs. 600 if the Rate increased to (R+2)%

=> SI = (P x 5 x (R+2))/100 = PR/20 + 10P/100

Hence,

PR/20 + 10P/100 = PR/20 + 600

=> P = 6000

Therefore, the sum invested is Rs. 6000

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Filed Under: Simple Interest
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13 6051