Aptitude and Reasoning Questions

Q:

X and Y entered into partnership with Rs. 700 and Rs. 600 respectively. After another 3 months, X withdrew two- sevenths of his stock but after 3 months, he puts back three-fifths of what he had withdrawn. The total profit at the end of the year is Rs. 726. How much of this should X receive?

A) Rs. 336 B) Rs. 366
C) Rs. 633 D) Rs. 663
 
Answer & Explanation Answer: B) Rs. 366

Explanation:

Profit ratio X & Y = (700 × 3) + (700 × 5/7× 3) + (700× 5/7 + 200 × 3/5 )× 6 : 600 ×12
X:Y= 7320 : 7200= 183:180
∴ X’s share from profit = 183 × 726/(183+180) = Rs. 366.

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Q:

A school committee of 5 is to be formed from 12 students.How many committees can be formed if John must be on the committee?

A) 11P4 B) 11C4
C) 11P5 D) 11C5
 
Answer & Explanation Answer: B) 11C4

Explanation:

If John must be on the committee,we have 11 students remaining,out of which we choose 4. So,11C4

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Q:

What is 85 of 352?

A) 21.5% B) 24.14%
C) 23.68% D) 25.47%
 
Answer & Explanation Answer: B) 24.14%

Explanation:

Here 85 of 352 => 85 is what percent in 352

Let p% of 352 is 85

Percentage(%) is generally calculated in the total of 100.

=> p x 352/100  = 85

=> p = 8500/352  = 24.14%

 

Hence, 85 is 24.14% of 352.

 

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Filed Under: Percentage
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4 5807
Q:

There are two examinations rooms P and Q. If 10 students are sent from P to Q, then the number of students in each room is the same. If 20 candidates are sent from Q to P, then the number of students in P is double the number of students in Q. The number of students in room Q is ?

A) 100 B) 70
C) 120 D) 80
 
Answer & Explanation Answer: D) 80

Explanation:

If 'k' is number of students in P and 'l' is number of students in Q, then
From the given conditions, we have
=> k - 10 = l + 10 .......(1)
=> k + 20 = 2(l - 20) ....(2)

Solving these eqns, we get
k = 100 and l = 80.
Therefore, number of students in class Q is 80.

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Filed Under: Arithmetical Reasoning
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3 5804
Q:

From a deck of 52 cards, a 5 card hand is dealt.How may distinct five card hands are there if the queen of spades and the four of diamonds must be in the hand?

A) 52C5 B) 50C3
C) 52C4 D) 50C4
 
Answer & Explanation Answer: B) 50C3

Explanation:

If the queen of spades and the four of diamonds must be in hand,we have 50 cards remaining out of which we are choosing 3.

 

So, 50C3

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0 5801
Q:

Which of the statements is sufficient to answer the question?


Question:
Find the sum of the first 10 numbers in the series.


Statements:
I. The first number is 2 and number is 20.
II. The common difference is 2.

A) only statement II is sufficient B) Only statement I is sufficient
C) Both statements I and II are sufficient D) Either statement I or II is sufficient
 
Answer & Explanation Answer: B) Only statement I is sufficient

Explanation:
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Filed Under: Statement and Assumptions
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2 5796
Q:

A Bus is running at 9/10 of its own speed reached a place in 22 hours. How much time could be saved if the bus would run at its own speed ?

A) 1.5 hrs B) 1.7 hrs
C) 2.2 hrs D) 3.5 hrs
 
Answer & Explanation Answer: C) 2.2 hrs

Explanation:

Let the original Speed be "s" kmph
And the usual time be "t" hrs
Given that if the bus is running at 9s/10 kmph the time is 22 hrs
=> [9s/10] x 22 = t x s
=> 99/5 = t
=> t = 19.8 hrs

 

Hence, if bus runs at its own speed, the time saved = 22 - 19.8 = 2.2 hrs.

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Filed Under: Time and Distance
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1 5795
Q:

O and O' are the center of the two circles with radii 7cm and 9cm respectively. The distance between the centers is 20cm. If PQ be the transverse common tangent to the circles, which cuts OO' at X, what is the length of O'X in cm ?

A) 10 B) 6
C) 35/4 D) 45/4
 
Answer & Explanation Answer: D) 45/4

Explanation:

As clear from the figure itself, triangle OQX and triangle O'PX are similar.

So,

OQ/O'P = OX/O'X

=> OX = (7/9)xO'X

And since, OX + O'X = 20

=> (7/9)xO'X + O'X = 20

=> O'X = 45/4

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Filed Under: Arithmetical Reasoning
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