Aptitude and Reasoning Questions

The correct pattern is +9,-7,+5,-3,+1
So,85 is wrong term and must be replaced by 90-3=87

Total quantity of sugar = 45 + 30 = 75

Gain or loss can be calculated as

9.75 x 75 - (30 x 9 + 45 x 10)

= 731.25 - 720

= 11.25

Hence, in the overall transaction, Rishi got Rs. 11.25 gain.

By observing the above pattern Figure (3) will complete the matrix.

The only possible way is BCAFDE
As D & F is not in any corner and E is after C and D. C is after B and before A
So the first person to join the institute is B

After servicing, the distance covered by car in 6 hours = 60 * 6 = 360 km Without servicing, speed of car = 50 kmph => Required time = Distance/speed = 360/50 = 7.2 hrs.

Here, S = {1, 2, 3, 4, ...., 19, 20}=> n(s) = 20
Let E = event of getting a multiple of 4 or 15
=multiples od 4 are {4, 8, 12, 16, 20}
And multiples of 15 means multiples of 3 and 5
= {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.
= the common multiple is only (15).
=> E = n(E)= 6
Required Probability = P(E) = n(E)/n(S) = 6/20 = 3/10.

Rate of her upstream = 12/2.5 = 4.8 km/hr

Then, ATQ

Rate of downstream = 4.8 x 3 = 14.4 km/hr

Hence, the distance she covers downstream in 5 hrs = 14.4 x 5 = 72 kms.

Let the speed of the train be 'S' kmph

From the given data,

Distance = Length of train = D = 200 mts = 200 x 18/5 kms

Time = 10 sec

given speed of the motorcycler = 12 kmph

Relative speed as they are moving in the same direction = (S - 12) kmph

$$\begin{gathered} (S- 12) = 200 x 18515 \\ S - 12 = 48 \\ S = 60 kmph \\ \end{gathered}$$

Hence, the speed of the train = S = 60 kmph

Now,

Let the speed of the jeep be 'x' kmph

$$\begin{gathered} 60 - x = 200 x 18520 \\ 60 - x = 36 \\ x = 60 - 36 \\ x = 24 kmph \end{gathered}$$

Therefore, the speed of the jeep = x = 24 kmph.