Aptitude and Reasoning Questions

i=j/m

PV=
FV(1+  i)^-n

Suppose the merchant will take advantage of the cash discount of 4% of $20 000 = $800 by paying the bill within 30 days from the date of invoice. He needs to borrow $20 000 = $800 = $19 200. He would borrow this money on day 30 and repay it on day 100 (the day the original invoice is due) resulting in a 70-day loan. The interest he should be willing to pay on borrowed money should not exceed the cash discount $800.

r=I/pt=21.73%

The highest simple interest rate at which the merchant can afford to borrow money is 21.73%. This is a break-even rate. If he can borrow money, say at a rate of 15%, he should do so. He would borrow $19 200 for 70 days at 15%. Maturity value of the loan is $19 200(1+0.15(70/365))=$19 752.33

savings would be $20 000 − $19 752.33 = $247.67

we know that speed = distance traveled/time taken
let the total distance traveled by the car is 2x km.
then time taken by it to cover first half is x/60 hour.
and for second half is x/40 hour.
Then average speed= total distance travelled / total time taken.

i.e. 2xx60+x40

=> 2x5x120

= 48 kmph.

The ratio of money she lended is

24000 : 16000 = 3 : 2

Let the rate of interest be R%

8%                   R%
     

           10

3          :           2

R = 13%.

Given 10 men take 15 days to complete a work

=> Total mandays = 15 x 10 = 150

Let the work be 150 mandays.

=> Now 37 men can do 150 mandays in 150/37 =~ 4 days

let speed of boat= X, speed of stream= Y
Upstream speed= X-Y
Downstream speed= X+Y
Sum of upstream & downstream= (X-Y) +(X+Y)= 2X
So, 2X= 40
X= 20 km/hr
Speed of boat : speed of stream= 600+100 :100= 7:1
So speed of Stream= 20/7 km/hr
ATQ, D/( X-Y) + D/( X+Y) = 5
D/(120/7) + D/(160/7)= 5
D= 480×5/49= 48.97 km= 50 Km(approx)

1. ANSWER : D 

Explanation -  Clearly the exports are more than the imports implies that the ratio of value of imports to exports in less than 1. So years are 1995, 1996, 1997 and 2000. So these are four years 

2. ANSWER : A 

Explanation - Clearly from the line graph we can judge it is minimum in year 1997.

3. ANSWER : C 

Explanation -  We are given with the ratio of imports and exports in the line graph.
Let the exports from the company in 1996 was x then, 

272/x = 0.85 

=> x = 272/0.85 

=> x = 320

Note: Please not that we are given the ratio of imports to exports, so export will will in denominator .

4. ANSWER : D 

Explanation - For calculating the percentage we will need value of exports, imports etc. We are only given with the ratio. So data in Inadequate.


Note: Please note in charts questions, most probably it includes 1 or more than 1 questions which are percentage based. So please clear percentage questions before preparing it. Because this is very scoring section.

5. ANSWER : B 

Explanation - The Ratio of imports to exports for the years 1998 and 1999 are 1.25 and 1.40 respectively. Let the exports in the year 1998 = Rs. x crores
Then,the exports in the year 1999 = (500-x) crores

=> 1.25 = 250/x [because 1.25 is 1998 ratio]

=> x = 250/1.25 = 200 crore

Thus the exports in the year 1999 were 500 - 200 = 300 crore

Let the imports in the year 1999 = Rs y crore 

Then 1.40 = y/300 

=> y = 1.40 x 300 = 420 crore