Aptitude and Reasoning Questions

Q:

Arrange the given words in the sequence in which they occur in the dictionary.


i. Obstacle
ii. Obscure
iii. Obsession
iv. Obstruct

A) iii, iv, i, ii B) i, iv, iii, ii
C) ii, iii, i, iv D) iv, iii, ii, i
 
Answer & Explanation Answer: C) ii, iii, i, iv

Explanation:
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Filed Under: Logical Sequence of Words
Exam Prep: AIEEE , Bank Exams , CAT

6 63660
Q:

If p = 72-72-72-72-....., then find the value of 2p2+1?

 

A) -129 B) -163
C) 129 D) 163
 
Answer & Explanation Answer: C) 129

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

1 63647
Q:

If Tan A = 15/8 and Tan B = 7/24, then Cos (A + B) = ?

 

A) 87/425 B) 304/425
C) 297/425 D) 416/425
 
Answer & Explanation Answer: A) 87/425

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Filed Under: Simplification
Exam Prep: Bank Exams

0 63610
Q:

Find the value of 76413+ 2713314

 

A) 7 B) 6
C) 49 D) 343
 
Answer & Explanation Answer: A) 7

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

2 63524
Q:

What value should come in place of the question mark (?) in the following question?

52x14+145018=1998÷?

A) 18.25 B) 19.98
C) 34.58 D) 65.25
 
Answer & Explanation Answer: B) 19.98

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0 63502
Q:

There are six persons A. B, C, D, E and F. C is the sister of F. B is the brother of E's husband. D is the father of A and grandfather of F. There are two fathers, three brothers and a mother in the group. Who is the mother ?

A) A B) B
C) C D) E
 
Answer & Explanation Answer: D) E

Explanation:

D is father of A and grandfather of F. So, A is father of F. 

Thus. D and A are the two fathers. C is the sister of F So. C is the daughter of A. 

Since there is only one mother, it is evident that E is the wife of A and hence the mother of C and F. 

So, B is brother of A There are three brothers. So. F is the brother of C. 

 Clearly, A is E's Husband.

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Filed Under: Blood Relations

806 63501
Q:

Select the figure which does not belong to the group:

 

 

 

A) C B) D
C) A D) B
 
Answer & Explanation Answer: B) D

Explanation:
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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 63485
Q:

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

A) 1/3 B) 3/5
C) 8/21 D) 7/21
 
Answer & Explanation Answer: A) 1/3

Explanation:

Total number of balls = (8 + 7 + 6) = 21.

Let E = event that the ball drawn is neither red nor green 

            = event that the ball drawn is blue.

n(E) = 7.

P(E) = n(E)/n(S) = 7/21 = 1/3.

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Filed Under: Probability

77 63466