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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Choose the correct alternative from the given ones that will complete the series.

GON, JRQ, MUT, ?

A) NOG B) PXW
C) JQR D) TUM
 
Answer & Explanation Answer: B) PXW

Explanation:
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Filed Under: Alphabet Test
Exam Prep: Bank Exams

0 26380
Q:

A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. What is the total distance traveled by the man ?

A) 4.58 kms B) 6.35 kms
C) 5.76 kms D) 5.24 kms
 
Answer & Explanation Answer: C) 5.76 kms

Explanation:

Speed in still water = 6 kmph

Stream speed = 1.2 kmph

Down stream  = 7.2 kmph

Up Stream = 4.8 kmph

x/7.2 + x/4.8 = 1

x = 2.88

Total Distance  = 2.88 x 2 = 5.76 kms

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

37 26371
Q:

Find the remainder in the expression 557 x 653 x 6729?

 

A) 0 B) 3
C) 5 D) 6
 
Answer & Explanation Answer: D) 6

Explanation:
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Filed Under: Problems on Numbers
Exam Prep: Bank Exams

1 26357
Q:

In a certain coding language, iF GO = 32 & SHE = 49 then SOME will be equal to ?

A) 56 B) 58
C) 62 D) 64
 
Answer & Explanation Answer: A) 56

Explanation:

If we count letters till the end of the alphabet including that letter in reverse order then
Here the values are nothing but the values corresponding to the alphabets when taken in a reverse order,i.e,A=26 ,B=25...,Z=1
G = 20 and O = 12 totaling 32
S = 8, H = 19 and E = 22 totaling 49

So
SOME = 8 + 12 + 14 + 22 = 56.

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Filed Under: Coding and Decoding
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE , TOEFL
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

102 26311
Q:

If Deepesh had walked 20 km/h faster he woulh have saved 1 hour in the distance of 60km. what is the usual speed of Deepesh?

A) 100 B) 120
C) 150 D) None of these
 
Answer & Explanation Answer: A) 100

Explanation:

Let the original speed  be x km/h, then

600x-600x+20=1 

 

⇒600x+20-xxx+20=1  

 

⇒x2+120x-12000=0

 

⇒x-120x-100=0

 

Therefore,  original speed = 100km/h

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Filed Under: Time and Distance

32 26287
Q:

A jar was full with honey. A person  used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated  the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar  solution. The initial amount of honey in the jar was filled with the sugar solution. The initial amount of honey in the jar was:

A) 1.25 kg B) 1 kg
C) 1.5 kg D) None of these
 
Answer & Explanation Answer: A) 1.25 kg

Explanation:

Let the initial amount of honey in the jar was K, then 

 512=K1-154    ∵ 20% =20100=15

        or      

512=K454

Therefore, K = 1250

Hence initially the honey in the jar= 1.25 kg

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Filed Under: Alligation or Mixture

32 26265
Q:

If the letters of the word CHASM are rearranged to form 5 letter words such that none of the word repeat and the results arranged in ascending order as in a dictionary what is the rank of the word CHASM ?

A) 32 B) 24
C) 72 D) 36
 
Answer & Explanation Answer: A) 32

Explanation:

The 5 letter word can be rearranged in 5!=120 Ways without any of the letters repeating.

The first 24 of these words will start with A.

Then the 25th word will start will CA _ _ _.
The remaining 3 letters can be rearranged in 3!=6 Ways. i.e. 6 words exist that start with CA.

The next word starts with CH and then A, i.e., CHA _ _.
The first of the words will be CHAMS. The next word will be CHASM.

Therefore, the rank of CHASM will be 24+6+2= 32

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Filed Under: Permutations and Combinations

17 26247
Q:

Read the question and answer from the given information.

 

Pravalika is studying 10th class, is Pravalika elder than Pranitha who is her classmate?

 

Argument 1: Yes, as she is her classmate Pranitha is younger to her

Argument 2: No, as she is classmate Pranitha is elder to her.

 

A) Neither I nor II follow B) Either I or II follow
C) Only II follow D) Only I follow
 
Answer & Explanation Answer: D) Only I follow

Explanation:
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Filed Under: Statement and Conclusions
Exam Prep: Bank Exams

2 26241