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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?

A) 110.12 meters B) 111.12 meters
C) 112.12 meters D) 113.12 meters
 
Answer & Explanation Answer: B) 111.12 meters

Explanation:

A runs 1000 meters while B runs 900 meters and C runs 800 meters.

Therefore, B runs 900 meters while C runs 800 meters.

So, the number of meters that C runs when B runs 1000 meters = (1000 x 800)/900 = 8000/9 = 888.88 meters

Thus, B can give C (1000 - 888.88) = 111.12 meters start

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Filed Under: Races and Games

22 21265
Q:

Arrange the given words in the sequence in which they occur in the dictionary.

i. Regular
ii. Reinforcement
iii. Rainbow
iv. Remedy

A) iii, i, iv, ii B) iv, i, iii, ii
C) iii, i, ii, iv D) iii, iv, i, ii
 
Answer & Explanation Answer: C) iii, i, ii, iv

Explanation:
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Filed Under: Logical Sequence of Words
Exam Prep: Bank Exams

0 21217
Q:

An accurate clock shows 7 o'clock in the morning. Through how may degrees will the hour hand rotate when the clock shows 3 o'clock in the afternoon?

A) 144º B) 168º
C) 180º D) 150º
 
Answer & Explanation Answer: C) 180º

Explanation:

Angle traced by the hour hand in 6 hours =360o12×6 = 180o.

 


 

 


 
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Filed Under: Clocks
Exam Prep: CAT
Job Role: Bank Clerk

41 21188
Q:

Which one of the following Venn diagrams best illustrates the three classes.

Rhombus, Quadrilaterals, Polygons

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: A) 1

Explanation:
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Filed Under: Logical Venn Diagram
Exam Prep: Bank Exams

7 21184
Q:

Use each of the following figures only once and form three groups. The three groups so formed are:

 



A) (1,5,7), (2,4,8), (3,6,9) B) (1,4,7), (2,5,8), (3,6,9)
C) (1,4,7), (3,5,8), (2,6,9) D) (1,4,7), (2,6,8), (3,5,9)
 
Answer & Explanation Answer: B) (1,4,7), (2,5,8), (3,6,9)

Explanation:
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Filed Under: Image Analysis
Exam Prep: Bank Exams

2 21182
Q:

5 men and 4 women are to be seated in a row so that the women occupy the even places . How many such arrangements are possible?

A) 2880 B) 1440
C) 720 D) 2020
 
Answer & Explanation Answer: A) 2880

Explanation:

There are total 9 places out of which 4 are even and rest 5 places are odd.

 

4 women can be arranged at 4 even places in 4! ways.

 

and 5 men can be placed in remaining 5 places in 5! ways.

 

Hence, the required number of permutations  = 4! x 5! = 24 x 120 = 2880

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Filed Under: Permutations and Combinations
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

8 21178
Q:

A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?

A) 2 : 1 B) 3 : 2
C) 25 : 18 D) 27 : 20
 
Answer & Explanation Answer: C) 25 : 18

Explanation:

Volume of the large cube = 33+43+53 = 216 cu.cm. 

Let the edge of the large cube be a. 

So, a3= 216 

=>a = 6 cm. 

Required ratio = 632+42+52662=2518

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Filed Under: Volume and Surface Area

18 21112
Q:

If in a certan language FASHION is coded as FOIHSAN, how is PROBLEM codedin that code?

A) PELBORM B) PRBOELM
C) RPBOELM D) RPBOELM
 
Answer & Explanation Answer: A) PELBORM

Explanation:

The first and the last letters of the word remain as such and the remaining letters are written in a reverse order, to obtain the code.

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Filed Under: Coding and Decoding

74 21107